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pickupchik [31]

3 years ago

6

How do you solve this? -5√112

1 answer:

3241004551 [841]3 years ago

3 0

Simplify the radicand by breaking the radicand up into a product of known factors.

Answer: -20<span>√7

</span>

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There are two calculus classes at your school. Both classes have a class average of 75.5. The first class has a standard deviati

Korvikt [17]

To compare the two classes, the Coefficient of Variation (COV) can be used. The formula for COV is this:
C = s / x
where s is the standard deviation and x is the mean
For the first class:
C1 = 10.2 / 75.5
C1 = 0.1351 (13.51%)

For the second class:
C2 = 22.5 / 75.5
C2 = 0.2980 (29.80%)

The COV is a test of homogeneity. Looking at the values, the first class has more students having a grade closer to the average than the second class.

4 0

2 years ago

Need help with 6,7,8,9,10,11,12,15

Ainat [17]

Answer:

6. 1.01 x -10^5

7. 6 x -10^14

8. 550,000

9. 60,700,000

10. 0.000204

11. 0.0004

12. 7,000,000,000,000 > 3,500,000,000

7,000,000,000,000 (or 7 x 10^12) is greater by 2,000 times

15. 10^3 and 10^4

7 0

3 years ago

Read 2 more answers

A new pair of skates cost $75. They are on sale for 10% off. Sales tax is 8%. If you purchased the skates, how much would you pa

Aleonysh [2.5K]

Answer:

72.9

Step-by-step explanation:

10% off 75 gets you to 67.5

8% more than 67.5 is 72.9

5 0

3 years ago

Which segment is both a chord and diameter segment____ . AO AE BC B

alexandr402 [8]

Answer:

Answer is BD

Step-by-step explanation:

7 0

3 years ago

Carlos is filling a spherical balloon with water. if he increases the volume of the balloon from 4,188.79 cubic centimeters to 1

Harrizon [31]

We know that the volume of a sphere of radius r is given by

$V=\frac{4}{3}\pi r^3$

Now, we have been given the initial volume was 4,188.79 cubic centimeters. Let us find the radius at this time.

Substituting the value of volume in the above equation, we get

$4,188.79=\frac{4}{3}\pi r^3\\
\\
4\pi r^3=4,188.79 \times 3\\
\\
r^3=\frac{4188.79 \times 3}{4\pi}\\
\\
r^3=1000\\
\\
r=10$

Now, the final volume is given by 14,137.167 cubic centimeters. Thus, we have

$14137.167 =\frac{4}{3}\pi r^3\\
\\
4\pi r^3=14137.167 \times 3\\
\\
r^3=\frac{14137.167\times 3}{4\pi}\\
\\
r^3=3375\\
\\
r=15$

Now, let us find the surface areas for these two radii.

For $r=10$

Surface area is given by

$S=4\pi r^2\\
\\
S=4\times 3.14 \times (10)^2\\
\\
S=1256 \text{ square centimeters}$

Similarly, for

$r=15\\
\\
S=4\times 3.14\times (15)^2\\
\\
S=2826 \text{ square centimeters}$

Therefore, the increase in the surface area is given by

$\Delta S= 2826-1256= 1570 \text{ square centimeters}$

Hence, the average rate at which the surface area is changing is given by

$\frac{1570}{12}=130.8$

Therefore, the average rate at which the surface area is changing is given by 130.8 square centimeters per second.

7 0

3 years ago