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VARVARA [1.3K]
3 years ago
7

determine the quadratic equations whose graph is given the vertex is (1,1) and the y intercept is (0,-7).

Mathematics
1 answer:
Zanzabum3 years ago
7 0

The vertex form of a quadratic equation is

... y = a(x -h)² + k . . . . . . where the vertex is (h, k) and "a" is some multiplier

Then using the given information, we can find "a".

... -7 = a(0 -1)² +1 = a+1

... -8 = a

The quadratic equation is

... y = -8(x -1)² +1 . . . . vertex form

or

... y = -8x² +16x -7 . . . . standard form

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the area of a parallelogram os 150 square meters the height of the parallelogram is 15 meters what is the length of the parallel
lys-0071 [83]
The length is 10 meters.

150 divided by 15 is 10.

Hope this helps!
3 0
3 years ago
If A+B= 45° then prove that: tanA+ tanB+ tanA. tanB​
Iteru [2.4K]

Answer:

See Explanation

Step-by-step explanation:

A+B= 45 \degree \\  \\ assuming  \:  \tan \: on \: both \: sides \\  \\\implies \: \tan( A+B)=  \tan 45 \degree \\  \\  \implies \: \tan( A+B)=  1 \:  \: \\  (  \because \: \tan 45 \degree = 1) \\  \\ \implies \:  \frac{\tan \: A +\tan \: B }{1 - \tan \: A .\tan \: B }  = 1 \\  \\ \implies \: \tan \: A +\tan \: B = 1 - \tan \: A .\tan \: B \\  \\ \purple{ \implies }\:  \orange{ \bold{\tan \: A +\tan \: B  + \tan \: A .\tan \: B= 1 }} \\  \\ thus \: proved

8 0
2 years ago
Solve 5kx + 6 = 7kx for x.<br> А. x=3/k<br> в. х = -2/k<br> с. x =-3/k<br> D. x=2/k
slamgirl [31]

Answer:

A.  x = 3/k.

Step-by-step explanation:

5kx + 6 = 7kx

5kx - 5kx + 6 = 7kx - 5kx

6 = 2kx

x = 6 / 2k

x = 3/k.

7 0
3 years ago
26•26^8 i’m not sure how to solve this
alexira [117]

Answer:

26^9

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is the angle, in degrees, when the coordinate is <img src="https://tex.z-dn.net/?f=%28-%5Csqrt%7B2%7D%20%2F2%29%2C%20%5Csqr
Juliette [100K]

Answer:

135°

Step-by-step explanation:

seg AB=seg OB

tan ∠AOB = 1

∠AOB = 45°

∠AOC = 135°

8 0
2 years ago
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