Answer:
2.33 = BC
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp / adj
tan B = AC / BC
tan 25 = AC / 5
Multiply each side by 5
5 tan 25 = BC
2.331538291 = BC
To the nearest hundredth
2.33 = BC
A^2+B^2=C^2
18^2+80^2=C^2
324+6400=C^2
6724=C^2
*Squareroot*
82=C
Answer:
m<N = 76°
Step-by-step explanation:
Given:
∆JKL and ∆MNL are isosceles ∆ (isosceles ∆ has 2 equal sides).
m<J = 64° (given)
Required:
m<N
SOLUTION:
m<K = m<J (base angles of an isosceles ∆ are equal)
m<K = 64° (Substitution)
m<K + m<J + m<JLK = 180° (sum of ∆)
64° + 64° + m<JLK = 180° (substitution)
128° + m<JLK = 180°
subtract 128 from each side
m<JLK = 180° - 128°
m<JLK = 52°
In isosceles ∆MNL, m<MLN and <M are base angles of the ∆. Therefore, they are of equal measure.
Thus:
m<MLN = m<JKL (vertical angles are congruent)
m<MLN = 52°
m<M = m<MLN (base angles of isosceles ∆MNL)
m<M = 52° (substitution)
m<N + m<M° + m<MLN = 180° (Sum of ∆)
m<N + 52° + 52° = 180° (Substitution)
m<N + 104° = 180°
subtract 104 from each side
m<N = 180° - 104°
m<N = 76°
Answer:
40
Step-by-step explanation:
The first box is 2--> 16*3 divided by 24= 2
Second box is 40--> 5*24 divided by 3= 40
Hope it helps.
