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soldier1979 [14.2K]
3 years ago
11

Please help!!! ill mark brainliest!!

Mathematics
1 answer:
Schach [20]3 years ago
3 0

Answer:

where is the question

Step-by-step explanation:

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denis-greek [22]
4 times with 1 left over
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3 years ago
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Can someone help me and give me the work plz
Neko [114]

y = sqrt(9 * 16).

This formula is derived because of similar parts of similar right triangles.

It is called the geometric mean which you can google for right triangles that share a common side.

y = sqrt(144)

y = 12

D is the only possible answer.

=============

x = sqrt(9^2 + 12^2)

x = sqrt(81 + 144)

x = sqrt(225)

x = 15

=============

z = sqrt( (9 + 16)^2 - 15^2)

z = sqrt( 25^2 - 15^2)

z = sqrt(625 - 225)

z = sqrt(400)

z = 20

Answer D

z =

7 0
3 years ago
HELP please! I need Help. Pre-calc. I'm not sure how to solve this. 50 Points! Please It will be appreciated.
Brums [2.3K]

\large{\mathcal{QUESTION:}}

An elliptical mirror has an eccentricity of 0.8. The mirror is surrounded by a 2-inch wide golden frame and is 34 inches tall including the frame. If a replacement mirror is being cut from a rectangular sheet of glass, what is the minimum dimensions needed for the sheet of glass?

\large{\mathcal{ANSWER:}}

<u>B</u><u>.</u><u> </u><u>1</u><u>7</u><u> </u><u>i</u><u>n</u><u>c</u><u>h</u><u>e</u><u>s</u><em><u> </u></em><u>b</u><u>y</u><u> </u><u>8</u><u> </u><u>i</u><u>n</u><u>c</u><u>h</u><u>e</u><u>s</u>

5 0
2 years ago
Can someone give me the answer
geniusboy [140]

Answer:

y-intercept is -6

Step-by-step explanation:

this equation y=mx+b

so we only find the nu,ber the number in b

ex:b is 1, so 1is y-intercept

5 0
3 years ago
GIVING BRAINLIEST HELP ASAP! please tell me how you did it so I can learn it
Ne4ueva [31]

Answer:

Ok since u want to learn ill teach you :)

Get your 3 points and then your do this

Example= 3 power of 2 plus 5 power of 2

Then ur gonna add and get your answer hope this helps

(if u still don't get it ill just give u the answer)

7.2

Step-by-step explanation:

Hope u kinda got a good start on this :)

5 0
3 years ago
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