Peaks are the highest points of a graph, there are four peaks, which are on the line that corresponds with July, which would be summer.
The answers to question 1. are four, four, summer.
January is the lowest point of the graph which are between 0 and 10, so the average temperature for January would be around 5 degrees.
The highest peaks ( July) are around the 70 degree line.
The answer s for question 2 are 5 and 70 degrees.
Answer:
Your answer is 3 quarters, 2 nickels, and 4 pennies
Step-by-step explanation:
2 quarters plus 6 nickels plus 9 pennies is equal to 89 cents. So if we subtract 75(3 quarters) we get 14 which is less than 25 therefore we must only use nickels and pennies from now on. If we take 14 and subtract 10(2 nickels) we get 4 which less than 5 leaving us only to use pennies, which one a piece so it must be 4 pennies. Hope this helps!
Using conditional probability, it is found that there is a 0.7873 = 78.73% probability that Mona was justifiably dropped.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Fail the test.
- Event B: Unfit.
The probability of <u>failing the test</u> is composed by:
- 46% of 37%(are fit).
- 100% of 63%(not fit).
Hence:

The probability of both failing the test and being unfit is:

Hence, the conditional probability is:

0.7873 = 78.73% probability that Mona was justifiably dropped.
A similar problem is given at brainly.com/question/14398287