This can be written as:
9-x>10
-x>1 (subtract 9 from both sides)
x<-1 (divide both sides by -1 and change the inequality sign)
Hope this helps
Answer:
4
Step-by-step explanation:
Here,BC=1/2FH
BC=8/2
BC=4
This is the required answer
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Answer:
a = 12. b =1/6. g(x) = 12(1/6)^x
Step-by-step explanation:
g(x) =a * b^x.
First we should use the give values to us in the table which are x=0 then g(x) = 12 and if x =1, then g(x) = 2. We should plug in the value where x = 0 since any value to the power of 0 is 1. 12= a *b^0. 12=a *1. Then we will get the value of a which is 12. Then we plug in our second given value to find b. 2 = 12 * b^1. First we will divide both sides by 12 to find b. 2/12 = 1/6. since any value to the power of 1 is itself then b =1/6. Then you will have a = 12. b =1/6 so g(x) = 12(1/6)^x
Answer:
b = 40 and -40
Step-by-step explanation:
General form of Perfect square trinomial is a 2 + 2 a b + b 2
Therefore from 16 x 2 − b x + 25 a 2 = √ 16 x 2 , b 2 = 25 , then a = ± 4 x , b = ± 5 take consideration a=4x and b=-5 (different sign), then − b x = 2 ( 4 x ) ( − 5 ) − b x = − 40 x b = 40
The perfect square is ( 4 x − 5 ) 2 = 16 x 2 − 40 x + 25 .
if we consider a=4x and b=5 (same sign), then − b x = 2 ( 4 x ) ( 5 ) − b x = 40 x b = − 40
The perfect square is ( 4 x + 5 ) 2 = 16 x 2 + 40 x + 25 .
The first solution ( 4 x − 5 ) 2 is the best solution after comparing the expression given. I hope this helps, xx .
9514 1404 393
Answer:
see attached
Step-by-step explanation:
The domain is the horizontal extent. Since there are arrows on both ends of the graph, the horizontal extent is from -∞ to ∞.
The range is the vertical extent. The graph shows a minimum at y=-2, which value is in the range. Expressed in interval notation, it is [-2, ∞).
Please note that the "end behavior" of y tends to +∞ in for either direction of x.
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The graph is "increasing" where it has positive slope, for 3 < x. It is "decreasing" where it has negative slope, for x < 3.
The graph is positive where it is above the x-axis. The points on the x-axis are not part of the "positive" interval(s). You will note there are two intervals where the graph is positive. It isn't difficult to find the answer choice that is a union of two intervals.
The graph is negative where hit is below the x-axis. Again, the points at x=1 and x=5 are not part of that interval, so it is expressed using curved brackets.
