Small squares with sides 4 cm were cut from each of the corners of a square piece of cardboard. then it was folded into an open-
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Answer:
There are 165 ways to distribute the blackboards between the schools. If at least 1 blackboard goes to each school, then we only have 35 ways.
Step-by-step explanation:
Essentially, this is a problem of balls and sticks. The 8 identical blackboards can be represented as 8 balls, and you assign them to each school by using 3 sticks. Basically each school receives an amount of blackboards equivalent to the amount of balls between 2 sticks: The first school gets all the balls before the first stick, the second school gets all the balls between stick 1 and stick 2, the third school gets the balls between sticks 2 and 3 and the last school gets all remaining balls.
The problem reduces to take 11 consecutive spots which we will use to localize the balls and the sticks and select 3 places to put the sticks. The amount of ways to do this is As a result, we have 165 ways to distribute the blackboards.
If each school needs at least 1 blackboard you can give 1 blackbooard to each of them first and distribute the remaining 4 the same way we did before. This time there will be 4 balls and 3 sticks, so we have to put 3 sticks in 7 spaces (if a school takes what it is between 2 sticks that doesnt have balls between, then that school only gets the first blackboard we assigned to it previously). The amount of ways to localize the sticks is . Thus, there are only 35 ways to distribute the blackboards in this case.
We need to use the pythagorean theorem
a^2 + b^2 = c^2
where a and b are the legs, and c is the hypotenuse
47^2 + 18^2 = c^2
c = sqrt(2533)
c = 50.33
The length of the wire is 50.33 meters.
(See attached image.)
a^2 + b^2 = c^2
where a and b are the legs, and c is the hypotenuse
47^2 + 18^2 = c^2
c = sqrt(2533)
c = 50.33
The length of the wire is 50.33 meters.
(See attached image.)