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nydimaria [60]
3 years ago
6

Small squares with sides 4 cm were cut from each of the corners of a square piece of cardboard. then it was folded into an open-

top box. find the original dimensions of the square piece of cardboard if the volume of this box is 144 cm3.
Mathematics
1 answer:
DENIUS [597]3 years ago
7 0
Suppose the length of the card board was x cm by x cm
After squares of 4cm was cut from the corner, the dimension for the box will be:
length=(x-8) cm
width=(x-8) cm
height=4 cm
thus the volume will be:
V=length*width*height
V=4×(x-8)×(x-8)=144
x²-16x+64=36
this can be simplified to form a quadratic equation given by:
x²-16x+28=0
solving the quadratic equation we get:
x=2 or x=14
Thus we conclude that the original dimensions was:
length=14 cm ; width=14 cm
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Anonymous 3 years ago
amm1812
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Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.

From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
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3 years ago
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5 0
2 years ago
Read 2 more answers
Multiplies to -1120 adds to 3
TEA [102]
With these, always write out the multiples first.

Start like this:
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3 years ago
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