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olasank [31]
2 years ago
9

Ellie started work at 8

Mathematics
2 answers:
Vadim26 [7]2 years ago
7 0

Answer:

9.25

Step-by-step explanation:

Mumz [18]2 years ago
5 0

Answer: 9.25!

Step-by-step explanation:

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BRAINLIEST ANSWER!! ASAP<br><br> 3(x+1)+6=-9<br> PLEASE EXPLAIN HOW YOU GOT THE ANSWER
Kryger [21]

Answer:

x=-6

Step-by-step explanation:

use distributive property on the () and times x and 1 by three

then you subtract 6 from both sides

then subtract three from both sides

then divide both sides by 3

your work would look like this:

3(x+1)+6=-9

3x+3+6=-9

3x+3=-15

3x=-18

x=-6

Hope this helps!

8 0
3 years ago
Read 2 more answers
Identify the like terms in the expression. -3x^2+3x-x^2-2+6x
ololo11 [35]

like terms: -3x^2, -x^2

and 3x, 6x

6 0
3 years ago
Can anyone help................
Mila [183]

x + 77 + 47 + 2x + x = 360

4x = 236

You answer: x = 59

59+77+59+47+59+59=360

7 0
3 years ago
Read 2 more answers
What is 440 yards in to miles
Alex17521 [72]
There is 1760 yd in a mile so to get your answer.

you would do 440 / 1760= .25

so .25 mile is your answer
7 0
2 years ago
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Milton spilled some ink on his homework paper. He can't read the coefficient of $x$, but he knows that the equation has two dist
Lera25 [3.4K]

Answer:

Sum = -81

Step-by-step explanation:

See the comment for complete question.

Given

c = 36 ----- Constant

No coefficient of x^2

Required:

Determine the sum of all distinct positive integers of the coefficient of x

Reading through the complete question, we can see that the question has 3 terms which are:

x^2 ---- with no coefficient

x ---- with an unknown coefficient

36 ---- constant

So, the equation can be represented as:

x^2 + ax + 36 = 0

Where a is the unknown coefficient

From the question, we understand that the equation has two negative integer solution. This can be represented as:

x = -\alpha and x = -\beta

Using the above roots, the equation can be represented as:

(x + \alpha)(x + \beta) = 0

Open brackets

x^2 + (\alpha + \beta)x + \alpha \beta = 0

To compare the above equation to x^2 + ax + 36 = 0, we have:

a = \alpha + \beta

\alpha \beta = 36

Where: \alpha, \beta and \alpha \ne \beta

The values of \alpha and \beta that satisfy \alpha \beta = 36 are:

\alpha = -1 and \beta = -36

\alpha = -2 and \beta = -18

\alpha = -3 and \beta = -12

\alpha = -4 and \beta = -9

So, the possible values of a are:

a = \alpha + \beta

When \alpha = -1 and \beta = -36

a = -1 - 36 = -37

When \alpha = -2 and \beta = -18

a = -2 - 18 = -20

When \alpha = -3 and \beta = -12

a = -3 - 12 = -15

When \alpha = -4 and \beta = -9

a = -4 - 9 = -13

At this point, we have established that the possible values of a are: -37, -20, -15 and -9.

The required sum is:

Sum = -37 -20 -15 - 9

Sum = -81

7 0
3 years ago
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