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Veseljchak [2.6K]
2 years ago
11

This is easy but please help a nika out !!

Mathematics
1 answer:
Feliz [49]2 years ago
8 0

Answer:

54 and 72

Step-by-step explanation:

3 plus 7

126 divided by 7

multiply 3 and 4 by 18

3 times 18 equals 54

4 times 18 equals 72

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PLS HELP ASAP THIS IS DUE SOON... WHOEVER ANSWERS FIRST WILL BE MARKED AS BRAINLYEST!!!!
Maru [420]

Answer:

40m^2    152.6m^2

Step-by-step explanation:

7 0
3 years ago
Suppose you solved a second-order equation by rewriting it as a system and found two scalar solutions: y = e^5x and z = e^2x. Th
xenn [34]

Answer:

The solutions are linearly independent because the Wronskian is not equal to 0 for all x.

The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

3 0
3 years ago
Guys I need help with this one! USE BAR MODEL FOR THIS ONE
sveta [45]
16.5 because it would 165 divided by 10, so if you were to round it’s 17 because you can’t really get half a person.
7 0
3 years ago
Suppose $1000 is invested at a rate of 13% per year compounded monthly. (Round your answers to the nearest cent.)
masya89 [10]

Answer:

a.  $1010.83

b.$1066.77

c. $1138.00

d.$13,269.22

Step-by-step explanation:

Given the annual rate as 13%(compounded monthly) and the principal amount as $1000.

a. #first we calculate the effective annual rate;

i_m=(1+i/m)^m-1\\\\i_{12}=(1+0.13/12)^{12}-1=0.1380

The compounded amount after 1 month is therefore:

P_1=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_1=1000(1+0.1380)^{1/12}\\\\P_1=1010.83

Hence, the principle after one month is $1010.83

b. The principal after 6 months:

-From a above we have the effective annual rate as 0.1380 and our time is 6 months:

P_{6m}=P(1+i_m)^n, \ n=6m, P=1000, i_m=0.1380\\\\P_{6m}=1000(1+0.1380)^{6/12}\\\\=1066.77

Hence,  the principal after 6 months is $1066.77

c.The principal after 1 year:

-From a above we have the effective annual rate as 0.1380 and our time is 12 months:

P_{1y}=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_{1y}=1000(1+0.1380)^{12}\\\\P_{1y}=1138

Hence,  the principal after 1 year is $1138.00

d. The principal after 20years:

-From a above we have the effective annual rate as 0.1380 and our time is 20yrs:

P_{20y}=P(1+I_m)^n, n=1/12, i_m=0.1380, P=1000\\\\P_{20y}=1000(1+0.1380)^{12}\\\\P_{20y}=13269.22

Hence,  the principal after 20 years is $13,269.22

3 0
3 years ago
The graph shows f(x)=(x-h)^2 what is the value of h ?
AVprozaik [17]

Answer: <em>I think the value of k is equal to (-1.5).</em>

<em />

Step-by-step explanation: <em>When you plug it into the graphing calculator, you get that exact graph.</em>

5 0
2 years ago
Read 2 more answers
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