Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.
Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs
Solve for n
4n/9-n(1/5+1/4) = -3
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540
Total number of products bought
= n+n = 540+540 = 1080
Answer:
70, 140, 280, 350
Step-by-step explanation:
Obviously, it must have the factors 2, 5, 7 as a minimum, so the smallest value is 2×5×7 = 70.
Any of these primes can be added to the product. In increasing order, the smallest additional factors will be 2, 4, 5, 7, 8, 10, ...
So, the four smallest numbers with prime factors of 2, 5, and 7 are ...
70 = 2·5·7
140 = 2²·5·7
280 = 2³·5·7
350 = 2·5²·7
Wish I can help , but you didn’t show any fractions nor anything I can use to answer your question . Can you mark me brainliest for effort !?
Answer:
~Re-write the equation~
SOLVE:
5x(3)+4x (2-9)+(2x+1)+(2x2+x-3)
5(1)(3)=15
4(2-9)=8+36=44
2x+1=3
2x2+x-3:4(1)-3=1
15+44+3+1
ANSWER=63x
Step-by-step explanation:
I wasn't quite sure because of the way you wrote it but here's an answer!
