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3 years ago

Leo dug up 6 4/5 pounds of

Mathematics

1 answer:

Maurinko [17]3 years ago

7 0

6 4/5 = 6.8
4 1/2 = 4.5

6.8-4.5= 2.3

Answer: 2 3/10 more pounds of treasure

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A cylinder, cone, and sphere are shown below. The three figures have the same radius. The cylinder and cone have the same height

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I’m just trying so much better to talk now but it’s just a good 256

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2 years ago

Verify that (cos²a) (2 + tan² a) = 2 - sin² a....<br>

Sveta_85 [38]

Trigonometric Formula's:

$\boxed{\sf \ \sf \sin^2 \theta + \cos^2 \theta = 1}$

$\boxed{ \sf tan\theta = \frac{sin\theta}{cos\theta} }$

Given to verify the following:

$\bf (cos^2a) (2 + tan^2 a) = 2 - sin^2 a$

$\texttt{\underline{rewrite the equation}:}$

$\rightarrow \sf (cos^2a) (2 + \dfrac{sin^2 a}{cos^2 a} )$

$\texttt{\underline{apply distributive method}:}$

$\rightarrow \sf 2 (cos^2a) + (\dfrac{sin^2 a}{cos^2 a} ) (cos^2a)$

$\texttt{\underline{simplify the following}:}$

$\rightarrow \sf 2cos^2 a + sin^2 a$

$\texttt{\underline{rewrite the equation}:}$

$\rightarrow \sf 2(1 - sin^2a ) + sin^2 a$

$\texttt{\underline{distribute inside the parenthesis}:}$

$\rightarrow \sf 2 - 2sin^2a + sin^2 a$

$\texttt{\underline{simplify the following}} :$

$\rightarrow \sf 2 - sin^2a$

Hence, verified the trigonometric identity.

7 0

2 years ago

Read 2 more answers

Two dressmakers, Sue and Anne, sewed costumes for a local theater production. Sue sewing alone for 10 hours sewed some of the co

crimeas [40]

Answer:

Sue would have taken 15 hours to sew all the costumes.

Step-by-step explanation:

In 10 hours, Sue sewed 5 costumes (1 every 2 hours).

Sue= 5 costumes

Sue sewed in 10 hours, twice as many costumes as Anne in 16 hours. Then 5 is twice costumes than Anne produced. Therefore, Anne sewed 2.5 costumes.

Anne: 2.5 costumes

In total they had to sew 5+2.5= 7.5 costumes. Then Sue would have taken 7.5*2= 15 hours to sew them all.

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3 years ago

8. Given the radius and area of the circle, calculate the angle at the centre of the circle.

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The answer is c for this problem

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3 years ago

The perimeter of an equilateral triangle is at most 72, what would this be as an inequality?

Reptile [31]

at most is either that number or less

so x<=72 would be the inequality

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3 years ago