Answer:
How many drinks should be sold to get a maximal profit? 468
Sales of the first one = 345 cups
Sales of the second one = 123 cups
Step-by-step explanation:
maximize 1.2F + 0.7S
where:
F = first type of drink
S = second type of drink
constraints:
sugar ⇒ 3F + 10S ≤ 3000
juice ⇒ 9F + 4S ≤ 3600
coffee ⇒ 4F + 5S ≤ 2000
using solver the maximum profit is $500.10
and the optimal solution is 345F + 123S
A, B, D, and E are correct.
What makes these a function and the others not is that for each x value, there is only one y value. For C, for example, there are multiple y values for the x value of -2. The same goes for F.
A way to add fractions that always works is to multiply each numerator by the denominator of the other, then express the sum of products over the product of the denominators.

Here, you have
The sum is -1 1/12
Answer:
a lot of cool cars race to grannys house to stop the wolf LOLLL
Step-by-step explanation:
Answer:
Hey there!
5(v+3)-10v>-10
5v+15-10v>-10
-5v+15>-10
-5v>-25
v<5
Let me know if this helps :)