If I understand what you are asking, you can use the median as an average since it is not affected by the mean ( median is a measure of center). Since a mean is affected by outliers, it might lower the score if there are very low outliers. But note that if there are outliers way <em>greater </em>it can increase the average. You can use the Inter Quartile Range if shown on a box plot ( measure of variability).
i would just round 9.3 to 9 and 4.4 to 4 so i subtract 9-4 so that equals 5 so about a 5 mile diffrence
9/7 or 1 2/7 is the answer. im pretty sure its right.
Answer:
3x+7=10x
Step-by-step explanation:
you are just adding 7+3 then you add the vairable term
Answer: the rate of the passenger train is 100 mph.
Step-by-step explanation:
Let x represent the rate of the passenger train.
The rate of the freight train was 10 miles per hour slower than the rate of the passenger train. It means that the rate of the freight train is (x - 10) mph
The passenger train traveled 100 miles. It means that the time it took travel 100 miles is
100/x
In the same amount of time, it took a freight train to travel 90 miles. It means that the time it took travel 90 miles is
90/(x - 10)
Since the time is the same, then
100/x = 90/(x - 10)
Cross multiplying, it becomes
100(x - 10) = 90x
100x - 1000 = 90x
100x - 90x = 1000
10x = 1000
x = 100 mph
