1. -1/20
work: Write all numerators above the least common denominator: -8+2+5/20
*Calculate the sum or difference: -1/20
Hey there, Dudedan!
In a#b = a+2b, we have the first term, a, plus 2 times the second term, b.
Let's try that with 3#4.
3#4 = 3+2(4) =
3 + 8 = 11.
Hope this helps!
I don't know if you want the whole x+2 on the bottom or not, but I will put it on the bottom for now.
Replace x with (3+h)
f(3+h)=1/[(3+h)+2]
Now if it's supposed to be JUST x in the denominator...
Replace x with (3+h)
f(3+h)=1/(3+h)+2
Best wishes!
1,6,11,16,21,26 is what you would get if you add 5.
