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4 years ago

How do you simplify the expression

Mathematics

2 answers:

zepelin [54]4 years ago

5 0

PEMDAS
12-14=-2
-2-5=-7
-7-9=-16
-16-4=-20
-20 is the answer

lesya692 [45]4 years ago

5 0

The answer is negative 20. Using PEMDAS.
Parenthesis, Exponents,Multiplication, Divison,Addition and Subtraction.
12-59-4

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3 years ago

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mina [271]

Answer:

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Step-by-step explanation:

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4 years ago

Use the Distributive Property to simplify

Anon25 [30]

well what i got was:

the exact form: 233/28

decimal form: 7.96428571...

mixed number form: 7 27/28

not sure if this is right at all but i hope it helps at least a little

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3 years ago

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Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$

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2 years ago