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4 years ago

In circle O, which segment is a diameter? a) RC b) SD c) CO d) OH

Mathematics

2 answers:

kenny6666 [7]4 years ago

7 0

RC is your answer!

Hope this helps

-Jurgen

kupik [55]4 years ago

5 0

RC is the diameter. As you can see, it runs across the circle.

I hope this helped you.

Brainliest answer is always appreciated.

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In the figure, r//s

lys-0071 [83]

M < 2 = m < 6...corresponding angles

m < 5 = m < 8....vertical angles are congruent

5 0

3 years ago

Read 2 more answers

Which of these strategies would eliminate a variable in the system of equations? \begin{cases} 6x + 5y = 1 \\\\ 6x - 5y = 7 \end

IRISSAK [1]

Answer:

x = 0.667 and y = -0.6

Step-by-step explanation:

Given that,

6x + 5y = 1 ....(1)

6x - 5y = 7 ...(2)

We need to solve the above equations.

Subtract equations (1) and (2)

6x + 5y -(6x - 5y) = 1-7

6x+5y-6x+5y = -6

10y=-6

y = -0.6

Put the value of y in equation (1).

6x + 5(-0.6) = 1

6x = 1-5(-0.6)

6x = 4

x = 0.667

Hence, first step is to subtract equation (1) and (2) then put the value of y in equation (1).

3 0

3 years ago

The formula for the volume of a cylinder is V=πr2h. The cylinder to the right has an exact volume of 480π cubic meters. Find its

olya-2409 [2.1K]

Answer:

240/r = h

Step-by-step explanation:

480π = πr2h Write out the equation

480 = r2h Cancel out π on both sides

240 = rh Divide by 2 on both sides

240/r = h Divide by r to isolate h and get your answer

4 0

3 years ago

Read 2 more answers

Adina has a rectangular garden that measures 9 m wide by 13 m long. She wants to increase the area to 192 m^2 by increasing the

tensa zangetsu [6.8K]

Area=legnth times width
192=(9+x)(13+x)
solve
expand
192=117+22x+x^2
minus 192 both sides
0=x^2+22x-75
factor
0=(x-3)(x+25)
set to zero

x-3=0
x=3

x+25=0
x=-25
not possible since that gives negative legnths and widhs

increased by 3

shorter is 9
9+3=12

C is ansre

3 0

3 years ago

A rectangular lot whose perimeter is 380 ft is fenced along three sides. An expensive fencing along the lot's length cost $ 25

AlekseyPX

We have two widths of the same length plus one length

Let the width be $w$ and the length be $l$

Perimeter = 2×width + 2×length
$380 = 2w + 2l$
$380 = 2(w+l)$
$190 = w+l$ (equation 1)

The cost is $5 per foot on the width and $25 per foot on the length
Total cost = (5 × 2 × width) + (25 × length)
$3625 = 10w + 25l$ (equation 2)

We have two variables that we need to solve, so we will need to use the simultaneous equations method (either elimination or substitution)

Since equation 1 is given $190 = w + l$ , we can rearrange the equation to make $l$ the subject

$l=190-w$

then substitute this into equation 2

$3625 = 10w + 25l$
$3625=10w + 25(190-w)$
$3625=10w+4750-25w$
$3625=-15w+4750$
$15w = 4750 - 3625$
$15w = 1125$
$w = 1125/15$
$w = 75$

Substitute w = 75 back into 190 = w + l

190 = 75 + l
l = 190 - 75
l = 115

Answer:
Length = 115 feet
Width = 75 feet

7 0

3 years ago