Question

X2 + y2 + 42x + 38y − 47 = 0. The equation of this circle in standard form is

Answer 1

The Standard form of the equation of circle is (x+21)² + (y+19)² = 849

What is Standard form of circle?

To transform general form to a standard form, you can use completing the square method or you can convert this equation

x² + y² + Dx + Ey + F = 0 to x² + y² + (-2h)x + (-2k)y + (h²+k²-r²) = 0

Here, Given: x² + y² + 42x + 38y − 47 = 0

Required: Find the values of h, k, and r using this formula

x² + y² + (-2h)x + (-2k)y + (h²+k²-r²) = 0

On comparing we get,

-2h = 42

  h = 21

-2k = 38

 k = 19

-47 = h² + k² - r²

-47 = 21² + 19² - r²

   r² = 849

  r = √849

Thus, the Standard form of the equation of circle is (x+21)² + (y+19)² = 849

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brainly.com/question/11833983

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