HELPPPP PLZZZ!!!! I need this done soon
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Answer:
The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( -2 , 7)
To Find:
Equation of Line that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?
Solution:
..................Given
which can be written as
Where m is the slope of the line
∴
On Comparing we get
The Required line is Perpendicular to the above line.
So,
Product of slopes = - 1
Slope of the required line is -6
Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,
i.e equation in point - slope form
Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get
The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is
Answer:
Step-by-step explanation:
The equation of a circle is given by:
Where (h, k) is the center and r is the radius.
The center of the circle is (1, -4).
And the radius is 3.
Substitute:
Simplify. Thus, our equation is: