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stiks02 [169]
3 years ago
13

Estimate the square root of 14 to two decimal places

Mathematics
1 answer:
irakobra [83]3 years ago
4 0

Answer:

3.74

Step-by-step explanation:

First, we can place the square root of fourteen between it's two closest square roots:

√9 < √14 < 16

3 < √14 < 4

Now since 14 is closer to 16 than 9, we can do this:

3.9^2 = 15.21

3.8^2 = 14.44

3.7^2 = 13.69

We can see that √14 must be between 13.69, and 14.44, which are 3.7^2 and 3.8^2, so we know that √14 must be between those numbers. If we go even further, then:

3.72^2 = 13.83

3.73^2 = 13.91

3.74^2 = 13.98

3.75^2 = 14.06

We can see that 3.74^2 is the closest to 14, only .02 away from the actual number, so 3.74 is our estimate for the square root of fourteen.

Brainliest?

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x ,y are the numbers

x = 5y-3

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(5y-3) +y =27

combine like terms

6y-3=27

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divide by 6

y=5

x = 5y-3

x=5*5-3

x=22

the two numbers are 22 and 5


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In a sample of 42 burritos, we found a sample mean 1.4 lb and assumed that sigma equals.5. In a test of the hypothesis H subscri
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Answer:

D. 0.9953 (Probability of a Type II error), 0.0047 (Power of the test)

Step-by-step explanation:

Let's first remember that a Type II error is to NOT reject H0 when it is false, and the probability of that occurring is known as β. On the other hand, power refers to the probability of rejecting H0 when it is false, so it can be calculated as 1 - β.

To resolve this we are going to use the Z-statistic:

                                           Z = (X¯ - μ0) / (σ/√n)

where  μ0 = 1.2

            σ = 5

            n = 42

As we can see in part A of the attached image, we have the normal distribution curve representation for this test, and because this is a two-tailed test, we split the significance level of α=0.01 evenly into the two tails, 0.005 in each tail, and if we look for the Z critical value for those values in a standard distribution Z table we will find that that value is 2.576.

Now we need to stablish the equation that will telll us for what values of X¯ will we reject H0.

Reject if:

Z ≤ -2.576                                                          Z ≥ 2.576

We know the equation for the Z-statistic, so we can substitute like follows and resolve.

Reject if:

(X¯ - 1.2) / (5/√42) ≤ -2.576                          (X¯ - 1.2) / (5/√42) ≥ 2.576

X¯ ≤ -0.79                                                         X¯ ≥ 3.19

We have the information that the true population mean is 1.25, so we now for a fact that H0 is false, so with this we can calculate the probability of a Type II error:  P(Do not reject H0 | μ=1.25)

As we can see in part B of the attached image, we can stablish that the type II error will represent the probability of the sample mean (X¯) falling between -0.79 and 3.19 when μ=1.25, and that represents the shaded area. So now we now that we are looking for P(-0.79 < X¯ < 3.19 | μ=1.25).

Because we know the equation of Z, we are going to standardize this as follows:

P ( (-0.79 - 1.25) / (5/√42) < Z <  (3.19 - 1.25) / (5/√42) )

This equals to:

P(-2.64 < Z < 2.51)

If we go and look for the area under the curve for Z positive scores in a normal standart table (part C of attached image), we will find that that area is 0.9940, which represents the probability of a Type II error.

Therefore, the power of the test will be 1-0.9940 = 0.006

If we look at the options of answers we have, there is no option that looks like this results, which means there was a probable redaction error, so we are going to stay with the closest option to these values which is option D.

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