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mamaluj [8]
3 years ago
12

A password is 4 characters long and must consist of 3 letters and 1 of 10 special characters. If letters can be repeated and the

special character is at the end of the password, how many possibilities are there?
Mathematics
2 answers:
Lena [83]3 years ago
8 0
175760 is the answer
Galina-37 [17]3 years ago
4 0

1st digit = 1 of 26 letters

2nd digit = 1 of 26 letters

3rd digit = 1 of 26 letters

 4th digit = 1 of 10 special characters


26 x 26 x 26 x 10 = 175,760 possibilities

 

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rewona [7]

Answer:

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6 0
2 years ago
Read 2 more answers
Q # 4 anybody help me please
Marysya12 [62]

<u>Answer</u>

-5/3, -1,  0.7,  √2,   √5


<u>Explanation</u>

√5 = 2.236

-1 ⇒ this is less than 1.  

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8 0
2 years ago
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B

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The function g(x)=-7x-1
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g=-7x-1/x

Step-by-step explanation:

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Please guys I need your help for this question ASAPPp!!!
o-na [289]
yea they're equivalent cause to solve the second equation sqrt of x+1 plus 3 equals 8 you must subtract 3 from both sides and when you do that you get sqrt of x+1=5 and thats the same as the first equation
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