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3 years ago

Find midpoint (-6, 3) (4,-3)

Mathematics

1 answer:

Crank3 years ago

5 0

<h2>Coordinate of mid point = (1,0)</h2>

Step-by-step explanation:

Given points are (-6,3) and (4,-3)

$x_1=-6 ,$ $y_1=3$ , $x_2= 4$ and $y_2 = -3$

Coordinate of mid point $(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )$

$=(\frac{-6+4}{2} ,\frac{3+(-3)}{2})$

=(1,0)

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3 years ago

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

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We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

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Now,

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$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

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Hence,

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3 years ago

Find the 12th and 37th term for each arithmetic sequence.

shutvik [7]

Answer:

3. f(12) = -10; f(37) = -60

4. f(12) = -102; f(37) = -352

Step-by-step explanation:

3. Put the numbers in the formula and do the arithmetic:

f(12) = 12 -2(12-1) = 12 -22 = -10

f(37) = 12 -2(37-1) = 12 -72 = -60

4. The explicit formula for an arithmetic sequence with first term a1 and common difference d is ...

an = a1 +d(n -1)

Your sequence has a first term a1=8 and a common difference d=-10.

As above, fill in the numbers and do the arithmetic.

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3 years ago

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Nataly [62]

Answer:

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Step-by-step explanation:

To find the cost of each,

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