All categories

3 years ago

Find midpoint (-6, 3) (4,-3)

Mathematics

1 answer:

Crank3 years ago

5 0

<h2>Coordinate of mid point = (1,0)</h2>

Step-by-step explanation:

Given points are (-6,3) and (4,-3)

$x_1=-6 ,$ $y_1=3$ , $x_2= 4$ and $y_2 = -3$

Coordinate of mid point $(\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2} )$

$=(\frac{-6+4}{2} ,\frac{3+(-3)}{2})$

=(1,0)

You might be interested in

Shaquira is baking cookies to put in packages for a fundraiser. Shaquira has made 86 chocolate chip cookies and 42 sugar cookies

bija089 [108]

She can make 42 identical packages which contains 2 chocolate chip cookies and 1 sugar cookies.

86 / 2 = 43 chocolate chips cookies

42 / 1 = 42 sugar cookies

Though the chocolate chip cookies can make 43 packs, the sugar cookies cannot fulfill the extra pack for it only has 42 pieces. That is why the maximum number of package that has identical content is 42 packages.

8 0

3 years ago

Pleaseeeeee help i don’t get thisssss

qaws [65]

Answer:

I think the answer is 8

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

If f(x) = 7x+6 and g(x)=8x-4 find f(g(-2))

sp2606 [1]

Answer:

$f(g(-2))=-134$

Step-by-step explanation:

So we have the two functions:

$f(x)=7x+6\text{ and } g(x)=8x-4$

And we want to find f(g(-2)).

First, let's find g(-2):

$g(-2)=8(-2)-4$

Multiply:

$g(-2)=-16-4$

Subtract:

$g(-2)=-20$

Now, substitute:

$f(g(-2))=f(-20)$

Now, find the value of f(-20):

$f(-20)=7(-20)+6$

Multiply:

$f(-20)=-140+6$

Add:

$f(-20)=-134$

So:

$f(g(-2))=-134$

And we're done!

5 0

3 years ago

A flagpole casts a shadow of 30 ft. A boy standing next to the flagpole casts a shaow of 9ft. What is the height of the flagpole

morpeh [17]

20 ft because the shadow would be 3/2 of the height. 9 is 3/2 of 6 so the height would be 20 bc 30 is 3/2 of 20

6 0

2 years ago

This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an

oksano4ka [1.4K]

Answer:

a.) dx3x² + 2

Use the properties of integrals

That's

integral 3x² + integral 2

= 3x^2+1/3 + 2x + c

= 3x³/3 + 2x + c

= x³ + 2x + C

where C is the constant of integration

b.) x³ + 2x

Use the properties of integrals

That's

integral x³ + integral 2x

= x^3+1/4 + 2x^1+1/2

= x⁴/4 + 2x²/2 + c

= x⁴/4 + x² + C

c.) dx6x 5 + 5

Use the properties of integrals

That's

integral 6x^5 + integral 5

= 6x^5+1/6 + 5x

= 6x^6/6 + 5x

= x^6 + 5x + C

d.) x^6 + 5x

integral x^6 + integral 5x

= x^6+1/7 + 5x^1+1/2

= x^7/7 + 5/2x² + C

Hope this helps

8 0

3 years ago