<img src="https://tex.z-dn.net/?f=2x%5E2%2B40%3D0" id="TexFormula1" title="2x^2+40=0" alt="2x^2+40=0" align="absmiddle" class="l

Sergeu [11.5K]

3 years ago

atex-formula">

Mathematics

1 answer:

aalyn [17]3 years ago

7 0

Answer:

x^2 = -20

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

The complete question in the attached figure

Let

x ----> the length of one leg of the triangle

we know that

In the right isosceles triangle of the figure

The cosine of angle of 45 degrees is equal to the adjacent side to angle of 45 degrees divided by the hypotenuse

$cos(45\°)=\frac{x}{22\sqrt{2}}$ ---> equation A

$cos(45\°)=\frac{\sqrt{2}}{2}$ ----> equation B

equate equation A and equation B and solve for x

$\frac{x}{22\sqrt{2}}=\frac{\sqrt{2}}{2}$

$x=\frac{\sqrt{2}}{2}(22\sqrt{2})=22\ units$

therefore

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