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denpristay [2]
3 years ago
8

Find the coordinates of the image after a reflection across x=3

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
5 0
Answer is D.
Have a nice day!
wlad13 [49]3 years ago
3 0
The correct answer is D
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What is -14+5k-3= simplifying​
andrew11 [14]

Answer:

5k-17

Step-by-step explanation:

-14+5k-3=5k-14-3=5k-17

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3 years ago
A right triangle has legs that are 21 in. and 25 in. long. What is the area of the triangle?
vfiekz [6]

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The area of the right triangle is 262.5

Step-by-step explanation:

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3 years ago
If 2d = 5c, then all of the following are true except _____.
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D is the only one not true
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Read 2 more answers
What is the equation of a circle whose center at (-5, -2) and radius is 2?​
aliya0001 [1]

The equation of a circle whose centre (-5,-2) and radius 2 is x^{2}+y^{2}+10x+4y+25=0

What is equation of a circle?

A circle is a closed curve drawn from a fixed point called centre of the circle. The distance between the centre of the circle and the arc of the circle is called the radius of the circle.

The equation of a circle with centre (h, k) radius r is

(x-h)^{2} +(y-k)^{2}=r^{2}

Given center = (-5,-2)  and Radius = 2

Put the Given value in the equation:

= (x-(-5))^{2} +(y-(-2))^{2} = 2^{2}

= (x+5)^{2} +(y+2)^{2}=2^{2}

= (x^{2} +10x+25)+(y^{2}+4y+4)= 4

= x^{2} +y^{2}+10x+ 4y+ 29 = 4

= x^{2} +y^{2}+10x +4y+ 29-4=0

= x^{2} +y^{2}+10x+4y+25=0

So, the equation of the circle whose centre is (-5,-2) and Radius 2 is

x^{2}+y^{2}+10x+4y+25=0

To read more about the equation of a circle. you can follow:

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6 0
2 years ago
Can somebody help me please ​
lisabon 2012 [21]

Answer:

Step-by-step explanation:

a - 7 = 3(b + 2)

a - 7 = 3b + 2*3

a - 7 = 3b + 6           {Subtract 6 from both sides}

a - 7 - 6 = 3b

a - 13  = 3b         {Divide both sides by 3}

b =\frac{a-13}{3}

5 0
3 years ago
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