Answer:
2 hours
Step-by-step explanation:
Given


Required
Determine the hours when the charges are the same
To do this, we simply equate both expressions:


Collect Like Terms


Divide both sides by -22

Rearrange

to give

Let

be a variable 'p' and so we can write

as

Rewrite the equation in terms of 'p'

where

using the quadratic formula

and subsitute the value of



There are two value of p; 125 and -27
Now we find the value of x
Earlier we substitute

for

and

for

When

,
![x= \sqrt[3]{125}=5](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B3%5D%7B125%7D%3D5%20)
When
![p = -27, x= \sqrt[3]{-27}=-3](https://tex.z-dn.net/?f=p%20%3D%20-27%2C%20x%3D%20%5Csqrt%5B3%5D%7B-27%7D%3D-3%20)
So the final answer is the two values of x;
x = 5 OR x = -3
14-3^2 x (-2)
=14-9 x (-2)
=14- (-18)
=32
Answer:
12
Step-by-step explanation:
a=bh x 1/2
If you plug in 3=b and 8=h it is now
a= 3 x 8 x 1/2
3x8 is 24 times 1/2 is 12
Hope this helps :)
<span>Multiplication takes precedence
</span>Execute the command multiplication bracket
3x + 2* (x - 1) - 4 =
3x + 2* x + 2* (-1 ) - 4 =
3x + 2x - 2 - 4 =
<span>We reduce similar words
</span>
3x + 2x - 2 - 4 =
5x - 6
Answer B