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tensa zangetsu [6.8K]
4 years ago
14

Find all zeros of f(x)= x^3-4x^2-5x+20

Mathematics
1 answer:
Anastasy [175]4 years ago
5 0
Possible roots are the factors of 20:  {1, 2, 4, 5, 10, 20} and their negatives.

Use synthetic division.  For example, if I chose 4 as a possible root, the synthetic division setup would be

     ____________
4  /  1   -4   -5   20
            4     0   -20
     _____________
       1    0    -5     0

This tells us that 4 is a root (I was just lucky) and (x-4) is a factor.

The quotient (remaining factor) is (x^2 - 5), which, if factored, yields 

x = sqrt(5) and x = -sqrt(5)


In summary, the roots (or zeros) of   <span>f(x)= x^3-4x^2-5x+20  are
 {sqrt(5), -sqrt(5), 4}</span>
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I'll give you brainliest! Just need help with 5-10! (Least common factors)
umka2103 [35]

Answer:

  • 60
  • 30
  • 48
  • 42
  • 45
  • 55

Step-by-step explanation:

5.

12,\:30\\\\\mathrm{Prime\:factorization\:of\:}12:\quad 2\times\:2\times\:3\\\mathrm{Prime\:factorization\:of\:}30:\quad 2\times\:3\times\:5\\\\=2\times\:2\times\:3\times\:5\\\\=60

6.

6,\:10\\\\\mathrm{Prime\:factorization\:of\:}6:\quad 2\times\:3\\\mathrm{Prime\:factorization\:of\:}10:\quad 2\times \:5\\\\=2\times \:3\times \:5\\\\=30

7.

16,\:24\\\\\mathrm{Prime\:factorization\:of\:}16:\quad 2\times \:2\times\:2\times\:2\\\mathrm{Prime\:factorization\:of\:}24:\quad 2\times\:2\times\:2\times\:3\\\\=2\times\:2\times\:2\times\:2\times\:3\\\\=48

8.

14,21\\\\\mathrm{Prime\:factorization\:of\:}14:\quad 2\times\:7\\\mathrm{Prime\:factorization\:of\:}21:\quad 3\times\:7\\\\=2\times\:7\times\:3\\\\=42

9.

9,15\\\\\mathrm{Prime\:factorization\:of\:}9:\quad 3\times\:3\\\mathrm{Prime\:factorization\:of\:}15:\quad 3\times\:5\\\\=3\times\:3\times\:5\\\\=45

10.

5,\:11\\\\\mathrm{Prime\:factorization\:of\:}5:\quad 5\\\mathrm{Prime\:factorization\:of\:}11:\quad 11\\\\=5\times \:11\\\\=55

5 0
3 years ago
Work out the nth term in 9 6 3 0
Angelina_Jolie [31]

Answer:

nth term--n+3

Step-by-step explanation:

numbers increase by add three each time

8 0
3 years ago
What is the equation in point-slope form of a line that passes through the points (7, −8) and (−4, 6) ?
Gala2k [10]
(7,-8)(-4,6)
slope = 6 - (-8) / (-4 - 7) = (6 + 8) / -11 = -14/11

point slope : y - y1= m(x - x1)
(-4,6)...x1 = -4 and y1 = 6
now we sub
y - 6 = -14/11(x - (-4) =
y - 6 = -14/11(x + 4) <===
5 0
3 years ago
Read 2 more answers
9. On Johnny math test, he was asked to re-write the expression –3(x + 10) by using the distributive
kirill [66]

Answer:

No, he is incorrect because he forgot to multiple the negative by the x, and only multiplied 3 by x instead of -3 by x.

Step-by-step explanation:

The correct re-write of this expression is:

-3x - 30

5 0
3 years ago
PLEASE HELP ME!!!!!!!!
hjlf
The Answer Is 60
2.5 x 8 The Number Of Sides On That Shape Was 8 
2.5 x 8 = 20
20 times the radius 3
20 x 3 = 60
60cm^2

~Hope This Helps :)
Need More Help With Question Just Inbox Me 
Also Rate, Give Thanks, And Mark As Brainiliest. 
Thank You ;) 
4 0
3 years ago
Read 2 more answers
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