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2 years ago

What is the simplified form of 4(2x - 5) + 2(3x + Y)?

Mathematics

1 answer:

evablogger [386]2 years ago

5 0

Answer:

I think this is the answer! 2x3 + 5x2 - x - 6 let me know if it’s right :)

Step-by-step explanation:

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Given the points A and BThe coordinates of point A = ( 3 , 1 )The coordinates of point B = (-1 , -1)The midpoint of AB = ([?],[

mr Goodwill [35]

Given the points A and B

The coordinates of point A = ( 3 , 1 )

The coordinates of point B = (-1 , -1)

The midpoint of AB, is the point C

C will be calculated as following :

$C=\frac{A+B}{2}=\frac{(3,1)+(-1,-1)}{2}=\frac{(3-1,1-1)}{2}=\frac{(2,0)}{2}=(1,0)$

so, the midpoint of AB = (1 , 0 )

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1 year ago

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Georgia [21]

Step-by-step explanation:

When a number is grouped with the x in this problem it will move the graph right (if it is is minus) and it will

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3 years ago

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Simplify the expression 11+2/3(15-21a)

Delvig [45]

Answer:

21-14a

Step-by-step explanation:

You have to distribute the (2/3) into the (15-21a) then add it to the 11. So after distributing the (2/3) into the (15-21a) is (10-14a). Then add that to the 11

7 0

3 years ago

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Point a is at (-7,-7) and m is at (-6,-1) what are the coordinates of point b

AlekseyPX

Answer:

The coordinates of point b are (-5,5).

Step-by-step explanation:

Given:

Point a is at (-7,-7) and m is at (-6,-1).

So, to find the coordinates of point b.

Let a (-7,-7) be $(x_{1},y_{1})$ , m (-6,-1) and b $(x_{2} ,y_{2})$ .

Now, putting the formula to get the coordinates:

$m=\frac{x_{1}+x_{2}}{2} , \frac{y_{1}+y_{2}}{2}$

⇒ $(-6,-1)=\frac{-7+x_{2}}{2} , \frac{-7+y_{2}}{2}$

So, here we will make two equations to find the value of $x_{2} andy_{2}$ :

$-6=\frac{-7+x_{2}}{2}$

multiplying both sides by 2

⇒ $-12=-7+x_{2}$

⇒ $-5=x_{2}$

And, now same method for getting the value of $y_{2}$ .

$-1=\frac{-7+y_{2}}{2}$

multiplying both sides by 2

⇒ $-2=-7+y_{2}$

⇒ $5=y_{2}$ .

The value of $(x_{2} ,y_{2})$ = $(-5,5)$ .

Therefore, the coordinates of point b are (-5,5).

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4 years ago

Which Of the following is the solution to 4|x+3|>8?

Shalnov [3]

Too bad you haven't shared illustrations of the possible solutions.

Starting with 4|x+3|>8, div. both sides by 4: <span>|x+3|>2

Case 1: x+3 is already positive: then x+3>2, or x > -1

Case 2: x+3 is negative: Then -(x+3)>2, or -x - 3 > 2, or -5>x or x<-5

Draw a number line representing x values. Place empty circles at x = -5 and x = -1. Draw a vector from the circle at x = -1, to the right of x = -1. Draw a vector from the circle at x = - 5, to the left of x = -5. Note that x values between x = -5 and x = -1 are not solutions.</span>

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3 years ago