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3 years ago

What is an angle between a side of a polygon and the extension of its adjacent side

Mathematics

1 answer:

jek_recluse [69]3 years ago

8 0

I would say that the angle would be an exterior angle because it's usually between the side of the polygon connected by a line as an extension of the adjacent side.

here's an example. hope it helps!

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A market research analyst claims that 32% of the people who visit the mall actually make a purchase. You think that less than 32

Rainbow [258]

Answer:

E. -1.48

Step-by-step explanation:

The test statistic is:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the expected value, $\sigma$ is the standard deviation and n is the size of the sample.

A market research analyst claims that 32% of the people who visit the mall actually make a purchase.

This means that:

$\mu = 0.32$

$\sigma = \sqrt{0.32*0.68} = 0.4665$

You stand by the exit door of the mall starting at noon and ask 82 people as they are leaving whether they bought anything. You find that only 20 people made a purchase.

This means that $n = 82, X = \frac{20}{82} = 0.2439$

The value of the test statistic is about:

$t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$t = \frac{0.2439 - 0.32}{\frac{0.4665}{\sqrt{82}}}$

$t = -1.48$

So the correct answer is given by option E.

3 0

3 years ago

8+(-6)= help,,, i got 2 but dont know if it's right

Oduvanchick [21]

The answer is 2 u were right so yeah answer is 2

5 0

3 years ago

Read 2 more answers

Mabel scored 19 points more on her math test than Nancy. Phoebe scored 10 points less on her math test than Nancy. If Phoebe sco

Ierofanga [76]

23+10+19=52 so your answer is 52

4 0

3 years ago

Read 2 more answers

What is partial derivative of z=(2x+3y)^10 with respect to x,y?

maw [93]

Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.

$\dfrac\partial{\partial x}(2x+3y)^{10}=10(2x+3y)^9\times2=20(2x+3y)^9$

$\dfrac\partial{\partial y}(2x+3y)^{10}=10(2x+3y)^9\times3=30(2x+3y)^9$

Or, if you actually did want the second order derivative,

$\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8$

and in case you meant the other way around, no need to compute that, as $z_{xy}=z_{yx}$ by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because $z$ is a polynomial).