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tensa zangetsu [6.8K]
3 years ago
15

How do you find the missing number of a perfect square trinomial? 25x^2 - 60x + ___

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0

Answer:

  36

Step-by-step explanation:

Compare what you have to the square ...

  (a +b)^2 = a^2 +2ab +b^2

Your "a" is √(25x^2) = 5x

Your "2ab" is -60x. Since you know "a", you can find "b".

  2ab = -60x

  2(5x)b = -60x . . . . . . . substitute for "a"

  b = -60x/(10x) = -6

Then the missing term is b^2 = (-6)^2 = 36.

Your trinomial is ...

  25x^2 -60x +<u>36</u>

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The simplified expression should be
ab(5+9-1)
once factorized
8 0
3 years ago
Please help with this Math Question...
Nataly [62]

Answer: A

<u>Step-by-step explanation:</u>

f(x) = x³ + 4x² + 7x + 6

possible rational roots are ±{1, 2, 3, 6}

Try x = -2

-2 |   1   4   7   6

   <u>|   ↓  -2  -4  -6</u>

       1    2    3   0 ← remainder is 0 so x = -2 is a root  ⇒  (x + 2) = 0

The factored polynomial x² + 2x + 3 = 0 is not factorable so use the quadratic formula to find the roots.

a=1, b=2, c=3

x=\dfrac{-b\pm\sqrt{b^2-4ac} }{2a}

x=\dfrac{-(2)\pm\sqrt{(2)^2-4(1)(3)} }{2(1)}

x=\dfrac{-2\pm\sqrt{4-12} }{2}

x=\dfrac{-2\pm\sqrt{-8} }{2}

x=\dfrac{-2\pm2i\sqrt{2}}{2}

x = -1 \pm i\sqrt{2}

x = -1 + i\sqrt{2}       x = -1 - i\sqrt{2}

x - (-1 + i\sqrt{2})=0       x - (-1 - i\sqrt{2})=0

The factors are:

(x - 2)[x - (-1 + i\sqrt{2})][x - (-1 - i\sqrt{2})]




5 0
3 years ago
Tìm
vichka [17]

Answer:

you can eat this noddles then you will got answer

6 0
3 years ago
(3/5y^4)^-2 simplify this please
Usimov [2.4K]
(\frac{3}{5}y^4)^{-2}=(\frac{5}{3})^2y^{4\times-2}=\frac{25}{9y^8}
8 0
3 years ago
Every 6th voter gets a button. Every 7th voter gets a sticker. Which voter is the first to receive both items?
MrMuchimi

Answer:

42

Step-by-step explanation:

Use LCM of 6 and 7 to find a number that is the same:

6     12     18     24     30     36     42

7     14     21     28     35     42

Since 42 shows up in both, the 42th voter gets a button and sticker.

Hope this helped.

8 0
2 years ago
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