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slavikrds [6]
3 years ago
15

(3/5y^4)^-2 simplify this please

Mathematics
1 answer:
Usimov [2.4K]3 years ago
8 0
(\frac{3}{5}y^4)^{-2}=(\frac{5}{3})^2y^{4\times-2}=\frac{25}{9y^8}
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A person can pay $27 for a membership to the science Museum and then go to the museum for just a $1.00 per visit. What is the ma
HACTEHA [7]

Answer:

10

Step-by-step explanation:

27 + 1(10) = 37

7 0
3 years ago
Read 2 more answers
1 what is sum of the interior angles of ABCD what is the sum of the exterior angles of CHFE 3 which sides are parallel to CE 4 w
expeople1 [14]

Given that ABCD is a parallelogram, the sum of its interior angles is:
360°

<h3>What is a parallelogram?</h3>

A parallelogram is a rectilinear two-dimensional figure with four sides whose opposite sides are parallel. See the image attached.

<h3>What is the sum of the exterior angles of CHFE?</h3>

The sum of the exterior angles of any Triangle or any polygon is 360°. Hence, the sum of the exterior angles of CHFE (a polygon) is 360°.

<h3>Which sides are parallel to CE?</h3>

The sides that are parallel to CE are:

FH

AD and

<h3>IJ.

Which side is perpendicular to CE?</h3>

The side that are perpendicular to CE is side side HH, hence we can state that:

CE ⊥ EH, because both lines intersect each other at right angles.

<h3>What is the sum of ∠C and ∠H?</h3>

Because the sum of angles in a triangle is 180° and we already have ∠CEH to be equal to ∠90° hence,

∠C + ∠H? = 180° - 90°

= 90°

<h3>What is the measure of the exterior angles of a Regular Pentagon?</h3>

The measure of the exterior angles of a regular pentagon is 72°

Learn more about Parallelograms at:
brainly.com/question/970600
#SPJ1

5 0
2 years ago
Two objects were lifted by a machine. One object had a mass of 2 kilograms and was lifted at a speed of 2m/sec. the other had a
OLga [1]
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:

<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
     potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.

<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
     potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.

If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.

4 0
3 years ago
Convert: 100 yards to meters.
daser333 [38]
It is 91.44m i think


6 0
3 years ago
Read 2 more answers
When f(x) = x2+9 and g(x) = x-9, find f(x)-g(x).
ohaa [14]

Answer:

\huge{ \boxed{ \sf{ {x}^{2}  - x + 18}}}

Step-by-step explanation:

\underline{ \text{Given}}:

\sf{f(x) =  {x}^{2} +9  \: and \:  g(x) = x-9}

\underline{ \text{To \: find}} :  \sf{ \: f(x) \:  -  \: g(x)}

Put the values:

\mapsto{ \sf{ {x}^{2}  + 9 - ( x  - 9)}}

While subtracting , sign of each term of the second expression changes.

\mapsto{ \sf{ {x}^{2}  + 9 - x + 9}}

Add the numbers : 9 and 9

\mapsto{ \boxed{ \sf{{x}^{2}  - x + 18}}}

Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

5 0
3 years ago
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