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3 years ago

Christine drove 260 miles using 12 gallons of gas. At this rate, how many gallons of gas would she need to drive 286 miles?

Mathematics

2 answers:

irinina [24]3 years ago

7 0

Answer:

13.2 gallons

Step-by-step explanation:

286/260 *12 = 13.2

Hatshy [7]3 years ago

6 0

Answer:

about 13.2 gallons

Step-by-step explanation:

Easy way to calculate.

12 gallons divided by 260 miles

Take that answer and multiply it by 286.

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Q3. In a hydraulic lift, a 1400 N force is applied to a 0.5 m2 piston. Calculate the minimum surface area of the large piston to

blondinia [14]

Answer:

1.8m^2 approx

Step-by-step explanation:

Given data

P1= 1400N

A1=0.5m^2

P2=5000 N

A2=??

Let us apply the formula to calculate the Area A2

P1/A1= P2/A2

substitute

1400/0.5= 5000/A2

cross multiply

1400*A2= 5000*0.5

1400*A2= 2500

A2= 2500/1400

A2= 1.78

Hence the Area is 1.8m^2 approx

3 0

3 years ago

Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere

Ket [755]

Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

<u>Taylor series</u> expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$

$\text{f}(x)=e^{4x} \implies \text{f}(1)=e^4$

$\text{f}\:'(x)=4e^{4x} \implies \text{f}\:'(1)=4e^4$

$\text{f}\:''(x)=16e^{4x} \implies \text{f}\:''(1)=16e^4$

Substituting the values in the series expansion gives:

$e^{4x}=e^4+4e^4(x-1)+\dfrac{16e^4}{2}(x-1)^2+...$

Factoring out e⁴:

$e^{4x}=e^4\left[1+4(x-1)+8}(x-1)^2+...\right]$

<u>Taylor Series summation notation</u>:

$\displaystyle \text{f}(x)=\sum^{\infty}_{n=0} \dfrac{\text{f}\:^{(n)}(a)}{n!}(x-a)^n$

Therefore:

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

7 0

2 years ago

Evaluate (x + y)0 for x = 4 and y = 3.

Ksju [112]

Sice you are multiply by zero the answer is 0 because any number time 0 is 0. 3+4 =7 then times 0

6 0

4 years ago

Read 2 more answers

A solution of the inequality 2x + y < -3 in order pair

vlabodo [156]

its your ans have a nice day

3 0

3 years ago

American adults are watching significantly less television than they did in previous decades. In 2016, Nielson reported that Ame

goldenfox [79]

Answer:

1. 0.271 = 27.1% probability that an average American adult watches more than 309 minutes of television per day.

2. 0.417 = 41.7% probability that an average American adult watches more than 2,250 minutes of television per week.

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the normal distribution.

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\lambda$ is the mean in the given interval, which is the same as the variance.

Normal distribution:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The Poisson distribution can be approximated to the normal with $\mu = \lambda, \sigma = \sqrt{\lambda}$

In 2016, Nielson reported that American adults are watching an average of five hours and twenty minutes, or 320 minutes, of television per day.

This means that $\lambda = 320n$ , in which n is the number of days.

1. Find the probability that an average American adult watches more than 309 minutes of television per day.

One day, so $\mu = 320, \sigma = \sqrt{320} = 17.89$

This probability is 1 subtracted by the pvalue of Z when X = 309. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{309 - 320}{17.89}$

$Z = 0.61$

$Z = 0.61$ has a pvalue of 0.729

1 - 0.729 = 0.271

0.271 = 27.1% probability that an average American adult watches more than 309 minutes of television per day.

2. Find the probability that an average American adult watches more than 2,250 minutes of television per week.

$\mu = 320*7 = 2240, \sigma = \sqrt{2240} = 47.33$

This is 1 subtracted by the pvalue of Z when X = 2250. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{2250 - 2240}{47.33}$

$Z = 0.21$

$Z = 0.21$ has a pvalue of 0.583

1 - 0.583 = 0.417

0.417 = 41.7% probability that an average American adult watches more than 2,250 minutes of television per week.

6 0

3 years ago