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11Alexandr11 [23.1K]
3 years ago
15

Christine drove 260 miles using 12 gallons of gas. At this rate, how many gallons of gas would she need to drive 286 miles?

Mathematics
2 answers:
irinina [24]3 years ago
7 0

Answer:

13.2 gallons

Step-by-step explanation:

286/260 *12 = 13.2

Hatshy [7]3 years ago
6 0

Answer:

about 13.2 gallons

Step-by-step explanation:

Easy way to calculate.

12 gallons divided by 260 miles

Take that answer and multiply it by 286.

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Answer:

The total balance for the month after one month of interest accrues is $561 .

Step-by-step explanation:

Given as :

The principal credit in account = p = $550

The rate of interest = 24% annual

The time period = 1 month = \dfrac{1}{12} year

Let The Amount after one month of interest = $A

<u>Now, From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal \times \textrm rate\times \textrm time}{100}

Or, s.i = \dfrac{\textrm p \times \textrm r\times \textrm t}{100}

Or, s.i = \dfrac{550\times 24\times \frac{1}{12}}{100}

Or, s.i = \dfrac{13200}{1200}

Or, s.i = 11

∵ Amount = Principal + interest

So, A = s.i + p

Or, A = $11 + $550

∴  A = $561

So, The amount after one month on interest = A = $561

Hence, The total balance for the month after one month of interest accrues = A = $561 . Answer

4 0
4 years ago
8.98*5.67 Put in decimal form
sweet-ann [11.9K]

Answer:

50.9166

Not sure what you mean by decimal form cause it is already in decimal form...

If you meant fraction form it would be 254583 /5000​

hope this helped! :)

8 0
3 years ago
Acute, obtuse, or right?
dimaraw [331]
It would be obtuse.


Hope this helps :)
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Answer:

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Step-by-step explanation:

Let us take F(x_1,x_2)=b_0x_2+b_1x_1+b_2x_2 and a constant \lambda \in \mathbb{R}. It holds that

F(\lambda x_1, \lambda x_2)=b_0\lambda x_2+b_1\lambda x_1+b_2\lambda x_1=\lambda(b_0x_2+b_1x_1+b_2x_2)=\lambda F(x_1,x_2)

which shows that F(x_1,x_2) is homogeneus of degree 1.

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