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Thepotemich [5.8K]

3 years ago

13

When the polynomial is written in standard form, what are the values of the leading coefficient and the constant? 5x + 2 - 3x^2

1 answer:

earnstyle [38]3 years ago

7 0

Leading coefficient = -3
Constant = 2

When you order them in standard form, you need to put them in ascending order of the exponents. Therefore the -3x^2 would come first, which makes the number attached (-3) the lead coefficient.

Also, since the number (2) without an x attached would be last (due to the power of x technically being 0), than that is the constant.

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Anit [1.1K]

Answer:

27/64

Step-by-step explanation:

(7×16)+(5×64)64×16

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Find the lengths of the missing side . Simplify all radicals !!!<br> help mee!!!!!!

larisa86 [58]

Answer:

$e = 13\sqrt{2}$

$f = 13\sqrt{2}$

Step-by-step explanation:

The ∆ given is an isosceles ∆ with a right angle measuring 90°, and two congruent angles measuring 45° each.

Using trigonometric ratio formula, we can find the lengths of the missing side as shown below:

Finding e:

$sin(\theta) = \frac{opp}{hyp}$

$sin(\theta) = sin(45) = \frac{\sqrt{2}}{2}$

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Plug in the values into the formula

$\frac{\sqrt{2}}{2} = \frac{e}{26}$

Multiply both sides by 26

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$e = 13\sqrt{2}$

Since side e is of the same length with side f, therefore, the length of side f = $13\sqrt{2}$

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