Answer:
A
B
-
4
x
+
9
B
C
=
5
x
+
2
=
A
=
9
x/
B
+
2/
B
−
9
C
A
C
−
56
=
A
=
9
x
/B
+
2/
B
−
9
C
x=A=9x/B+2x/B-9C
I hope this helps
Answer:
Emilio will have both activities again on the same day after 90 days from this Saturday.
Step-by-step explanation:
<em>To solve this question list the multiples of 30 and 9 to find the first common multiple because the two activities will happen again in </em><em>a number divisible by both 30 and 9.</em>
∵ The multiples of 30 are: 30, 60, 90, 120, ............
∵ The multiples of 9 are: 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, 99, .....
→ The common multiple is 90
∴ The common multiple of 30 and 9 is 90
→ That means the activities will meet again after 90 days from
this Saturday
Emilio will have both activities again on the same day after 90 days from this Saturday.
Pi*r^2
3.14*7000^2
153,860,000
![a\cdot a\cdot a=216\\\\a^3=216\to a=\sqrt[3]{216}\\\\\boxed{a=6}\\\\\text{Substitute}\ b\cdot c=52\ \text{to the second expression}\ a\cdot b\cdot c=96:\\\\abc96\ \wedge\ bc=52\to a(52)=96\qquad\text{divide both sides by 52}\\\\a=\dfrac{96}{52}\to a=\dfrac{24}{13}\neq6](https://tex.z-dn.net/?f=a%5Ccdot%20a%5Ccdot%20a%3D216%5C%5C%5C%5Ca%5E3%3D216%5Cto%20a%3D%5Csqrt%5B3%5D%7B216%7D%5C%5C%5C%5C%5Cboxed%7Ba%3D6%7D%5C%5C%5C%5C%5Ctext%7BSubstitute%7D%5C%20b%5Ccdot%20c%3D52%5C%20%5Ctext%7Bto%20the%20second%20expression%7D%5C%20a%5Ccdot%20b%5Ccdot%20c%3D96%3A%5C%5C%5C%5Cabc96%5C%20%5Cwedge%5C%20bc%3D52%5Cto%20a%2852%29%3D96%5Cqquad%5Ctext%7Bdivide%20both%20sides%20by%2052%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B96%7D%7B52%7D%5Cto%20a%3D%5Cdfrac%7B24%7D%7B13%7D%5Cneq6)
a = 6 and a = 24/13 FALSE!!!
<h3>Answer: NO SOLUTION.</h3>
