<em><u>Significance of the Hudson River School in the antebellum era to the reaction to the exploitation of American environment during the Gilded Age was that it was warning against the environment exploitation because of factories established in the Gilded Age.
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Further Explanations:
Hudson River School was an American art school started in the antebellum era. The school was famous for numerous of painters of landscape, who were swayed by Romanticism. The paintings were revealing the beauty of Hudson River Valley and the landscape nearby it that includes the White Mountains, Adirondack, and Catskill.
Antebellum era and the gilded age are of the same epoch but are unquestionably dissimilar from each other. Glided age was the era in the United States marked by the monetary growth in the Northern and the Western areas of America. Rapid development of trades and arrival of numerous migrants was also marked during the epoch while the antebellum era refers to the era after the war that is marked by the nation’s expansion and economic reforms.
The painters of the schools were against industrialization as according to the industries will destroy the beauty of nature. Establishment of numerous industries leads to the destruction of forests and other natural resources.
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Answer Details
Grade: High school
Subject: US History
Chapter: Hudson River School
Keywords:
Hudson River School, American, art, antebellum era, landscape, Romanticism, Hudson River Valley, White Mountains, Adirondack, Catskill, Antebellum era, gilded age
Answer:
shoots are most pronounced where the muscovite is green or yellowish ... heavy demands for so-called "strategic" mica,
Explanation:
C. All the other ones are way off. I was thinking maybe D but it wasnt a law so C for sure
Answer:
5.71 x 10^13 C.
Explanation:
We are given the following parameters or data or information and these data are going to help us in solving this particular Question or problem effectively and efficiently;
=> mass of Earth = 5.98 × 10^ 24kg, mass of Moon = 7.35 × 10^22 kg and the radius of orbit = 3.84 × 10^8m.
Recall that H =( G × m1 × m2) / r^2. where m1 and m2 are the masses of the two bodies amd r is the radius.
We will be making use of the formula below:
the value of Q to maintain the present orbit = √ { ( 7.35 × 10^22 ) × (5.98 × 10^24) × 4 × π × V.
the value of Q to maintain the present orbit = 5.71 x 10^13 C.
