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Usimov [2.4K]
3 years ago
11

Simplify. 57x+12−32(3+5)−10

Mathematics
1 answer:
Anni [7]3 years ago
3 0
-32(3+5)+57x+12-10, -256+2+57x=57x-254 Answer
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(c^3b^1a^4)^4 + 3a^16b^4c^12
azamat

Answer: 4a16b4c12

Step-by-step explanation:

5 0
3 years ago
Solve the following equation <br><br>​
Alika [10]

Answer:

¶Emma Jess¶

Step-by-step explanation:

,

7 0
3 years ago
In a randomly selected sample of 1169 men ages 35–44, the mean total cholesterol level was 210 milligrams per deciliter with a s
Aneli [31]

Answer:

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 210, \sigma = 38.6

Find the highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10%.

This is the 10th percentile, which is X when Z has a pvalue of 0.1. So X when Z = -1.28.

Z = \frac{X - \mu}{\sigma}

-1.28 = \frac{X - 210}{38.6}

X - 210 = -1.28*38.6

X = 160.59

The highest total cholesterol level a man in this 35–44 age group can have and be in the lowest 10% is 160.59 milligrams per deciliter.

5 0
3 years ago
A. Sam purchased 3 games for $140 after a discount of 30%. What was the original price?
Semmy [17]

Answer:

a) $175 b) It will be $126

Step-by-step explanation:

Cost price of 3 games= $140

Let the original price of games= $ x

Discount is given= 30%

According to question

x \frac{(100-20)}{100}= $140

x \frac{80}{100}= $140

x ×0.8= $140

x= $ \frac{$140}{0.8}

x= $175

Hence, the original price of games $ 140

(b)  If Sam had given a discount of 20%

Again a discount = 10%

The price of games=$ 140

Now, the selling price will be= 175\frac{(100-20)}{100}×\frac{(100-10)}{100}

Now, the selling price will be= $ 126

Hence, the price will be different.

7 0
3 years ago
A candy store in the mall orders 1000 boxes a month each box of candy weighs 45.9 grams . What is the total weight in grams of t
Degger [83]

Answer:

45900 grams

Step-by-step explanation:

All you need to do is multiply 45.9 grams by 1000 for the total combined weight of every box combined to get.

45.9 x 1000 = 45900

4 0
3 years ago
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