33/8 < exact form
4.125 < decimal form
4 1/8 < mixed number form
Answer: right isosceles ? i think
Step-by-step explanation:
Answer:
one solution with a y value of 5
Step-by-step explanation:
/| x+y-4 = 0| x-y-6 = 0
We try to solve the equation: x+y-4 = 0
x+y-4 = 0 // - x-4
y = -(x-4)
y = 4-x
We insert the solution into one of the initial equations of our system of equations
We get a system of equations:
/| x+x-6-4 = 0| y = 4-x
2*x-10 = 0 // + 10
2*x = 10 // : 2
x = 10/2
x = 5
We insert the solution into one of the initial equations of our system of equations
For y = 4-x:
y = 4-5
y = -1
We get a system of equations:
/| y = -1| x = 5
Function A:

. Vertical asymptotes are in the form x=, and they are a vertical line that the function approaches but never hits. They can be easily found by looking for values of <em>x</em> that can not be graphed. In this case, <em>x</em> cannot equal 0, as we cannot divide by 0. Therefore <em>x</em>=0 is a vertical asymptote for this function. The horizontal asymptote is in the form <em>y</em>=, and is a horizontal line that the function approaches but never hits. It can be found by finding the limit of the function. In this case, as <em>x</em> increases, 1/<em>x</em> gets closer and closer to 0. As that part of the function gets closer to 0, the overall function gets closer to 0+4 or 4. Thus y=4 would be the horizontal asymptote for function A.
Function B: From the graph we can see that the function approaches the line x=2 but never hits. This is the vertical asymptote. We can also see from the graph that the function approaches the line x=1 but never hits. This is the horizontal asymptote.