5x - 7y=28 -*+ 7y=0 A) (7,1) B) (-6,5) c) (7,5) D) (7,-1)

Mathematics

1 answer:

alexgriva [62]3 years ago

5 0

The answer is A (7,1)

Just substitute the (x,y) and plug it in to the equation

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$\square\quad{y=\dfrac{1}{2}x+4}\\\\\square\quad{\dfrac{y-5}{x-2}=\dfrac{1}{2}}$