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alexgriva [62]
3 years ago
7

Find the missing segment in the attached image

Mathematics
1 answer:
Digiron [165]3 years ago
4 0

Answer:

49 unit.

Step-by-step explanation:

concept used: basic proportionality theorem,

theorem states that, if a line is drawn parallel to one side of the triangle and intersect the other two sides then the two sides are divided in the same ratio.  

Example:

let there be a triangle ABC

if DE is drawn parallel to BC such that D is a point on line AB and E is other point on AC, then

AD/DB = AE/EC (basic proportionality theorem)

_____________________________________

Similarly in this problem ,

one side has length of 60 units,

The parallel line divides it at point such that one of the segment of this side is of 35 units.

Then other segment of same side = 60-35 = 25

now using basic proportionality theorem

?/35 = 35/25

=> ?/35 = 7/5

=> ? = 7/5 * 35 = 49

Thus, length of missing side segment is 49 unit.

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The height of a triangle is half the length of its base. The area of the triangle is 12.25cm. Find the height
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Answer:  The height of the triangle is:  " 3.5 cm " .
_______________________________________________________
<u>
Note</u>:
 The formula/equation for the area, "A" , of a triangle is:

           A = (1/2) * b * h  ;  or write as:  A = (b * h) / 2 ; 
_________________________________________________
 in which:   "A = area of the triangle" ; 
                  "b = base length" ; 
                  "h = "[perpendicular] height" ; 
_________________________________________________
     Given:  h = (b/2) ;
                  A = 12.25 cm²
{Note:  Let us assume that the given area was "12.25 cm² " .}. 
_________________________________________________
 We are to find the height, "h" ; 

The formula for the Area, "A", is:   A = (b * h) / 2 ; 

Let us rearrange the formula ;
 to isolate the "h" (height) on one side of the equation; 

→ Multiply EACH side of the equation by "2" ; to eliminate the "fraction" ; 

2*A = [ (b * h) / 2 ] * 2 ; 

   to get:   " 2A = b * h " ; 

↔    " b * h = 2A " ; 

Divide EACH SIDE of the equation by "b" ; to isolate "h" on one side of the equation: 

        →  (b * h) / b  = (2A) / b ; 

to get: 
  
        →   h  =  2A / b ; 

Since  "h = b/2" ; subtitute "b/2" for "h" ; 
 
Plug in:  "12.25 cm² " for "A" ;

       →  b/2  =  2A/b ;   →  Note:  " 2A/b = [2* (12.25 cm²) ] / b " ;

Note:  " 2* (12.25 cm²) = 24.5 cm² ; 

Rewrite as: 

       →  b/2  =  (24.5 cm²) / b ;
_____________________________________
Cross-multiply:   b*b = (24.5 cm²) *2 ; 

to get:   b² = 49 cm² ; 

Take the "positive square root" of each side of the equation" ; 
            to isolate "b" on one side of the equation ; & to solve for "b" ; 

             →  +√(b²)  =  +√(49 cm²) ; 

             →  b = 7 cm ; 

Now, we want to solve for "h" (the height) :
_________________________________________________________
             →  h = b / 2 = 7 cm / 2 = 3.5 cm ; 
_________________________________________________________
Answer:  The height of the triangle is:  " 3.5 cm <span>" .
</span>_________________________________________________________
6 0
3 years ago
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