Answer:
Replace all occurrences of y with 2x−1 in each equation.
0=0
y=2x−1
Remove any equations from the system that are always true.
y=2x−1
Step-by-step explanation:
To get the extrema, derive the function.
You get y' = 2x^-1/3 - 2.
Set this equal to zero, and you get x=0 as the location of a critical point.
Since you are on a closed interval [-1, 1], those points can also have an extrema.
Your min is right, but the max isn't at (1,1). At x=-1, you get y=5 (y = 3(-1)^2/3 -2(-1); (-1)^2/3 = 1, not -1).
Thus, the maximum is at (-1, 5).
The possiblities that exist:
H, H, H
H, H, T
H, T, H <----
H, T, T
T, H, H
T, H, T
T, T, H
T, T, T
The answer is 1/8. Now the problem that you gave us isn't dependent upon anything, so more specifically the answer is 1/8 independent.
Nothing has actually happened therefore no odds have been decreased or increased.
The answer is y equals 0.85 x. Hope this help you
Step-by-step explanation:
steps are in picture above.
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