9514 1404 393
Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
The answer the 3,
First you have to apply the exponent rule which is 1 - 3• 1/g
Then you multiply the fractions - 1•3/g
Then multiply the numbers 1 and 3, which is 3, so there you have it 3/g, or 3, they’re the same thing.
You would use unit rate for this. If Austin makes $209 in 11 hours, then he makes 209/11 = 19 dollars in 1 hour.
Then, we can make a proportion:
$19/1 hour = $152/ x hours
Cross multiply:
152 = 19x
Solve for x to get:
x = 8 hours.
Answer:
-1/3
Step-by-step explanation: