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Vladimir79 [104]
3 years ago
5

Evaluate 6 P 3. its an AQR course

Mathematics
1 answer:
ivolga24 [154]3 years ago
8 0
42
idk if its right havent did it in a long time
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I will mark brainliest to whoever has the best answer
gogolik [260]

Answer:

REPOST YOURE PICTURE

Step-by-step explanation:

3 0
3 years ago
I need the answer for question 15 a and b
trasher [3.6K]
A is 14 total 
B is yes because the gained 11 and lost 3 which means they gained 8 after taking away the ones lost and they are still on the positive side so they keep th ball.

7 0
3 years ago
Read 2 more answers
Solve the equation<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7Bx%20-%206%7D%20%20%2B%202%20%3D%206" id="TexFormula1" title
tensa zangetsu [6.8K]

Explanation:

First you had to square from both sides of equation form.

(\sqrt{x-6+2})^2=6^2

Then you expanded form.

(\sqrt{x-6+2})^2=x-4

x-4=36

6^2=6*6=36

Solve by equation form.

x-4=36

Add by four from both sides of equation form.

x-4+4=36+4

Simplify.

x=40

Verified solutions.

x=40 \boxed{TRUE}

Final answer: \boxed{x=40}

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

7 0
3 years ago
A student is trying to solve the set of two equations given below: Equation A: x + z = 6 Equation B: 3x + 2z = 1 Which of the fo
solong [7]
A) multiply equation A by -2 so you get -2x - 2z = -12 and then you can add both equations to eliminate z
8 0
3 years ago
Read 2 more answers
Use the sum and difference identities to find the exact values of the sine, cosine, and tangent of the angle. . 165 = 135 + 30
Serhud [2]
So lets get to the problem 

<span>165°= 135° +30° </span>

<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>

<span>Sin165° </span>
<span>= Sin ( 90° + 45°+30° ) </span>
<span>= Cos( 45°+30° )..... (∵ Sin(90 + θ)=cosθ </span>
<span>= Cos45°Cos30° - Sin45°Sin30° </span>

<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
<span>= -Sin( 45°+30° )..... (∵Cos(90 + θ)=-Sinθ </span>
<span>= Sin45°Cos30° + Cos45°Sin30° </span>


<span>Tan165° </span>
<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
<span>= -1/tan(45°+30°) </span>
<span>= -[1-tan45°.Tan30°]/[tan45°+Tan30°] </span>

<span>Substitute the above values with the following... These should be memorized </span>
<span>Sin 30° = 1/2 </span>
<span>Cos 30° =[Sqrt(3)]/2 </span>
<span>Tan 30° = 1/[Sqrt(3)] </span>
<span>Sin45°=Cos45°=1/[Sqrt(2)] </span>
<span>Tan 45° = 1</span>
4 0
3 years ago
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