Log₂(6x) - log₂(√x) = 2
log₂[6x/√x] = 2, let's rewrite it in terms of exponent:
(remember : ㏒₂(x) = a (in exponential form) → x = 2ᵃ
6x/√x = 2²
6x/√x = 4, square both sides:
36x²/x = 16 .Simplify:
36x = 16 and x = 16/36 . So x = 4/9
Your answer is going to be the first one: 3^2
The equation that you are looking for is y = -2x + 3
Answer:
The Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.
Step-by-step explanation: