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Ugo [173]
3 years ago
9

Gregg is a wedding photographer. He charges $500 for his basic package and $150 for each hour he is at the wedding. Which equati

on can be used to find w, the cost for a wedding that lasts 5 hours?
Mathematics
1 answer:
aleksklad [387]3 years ago
8 0
The equation that best fits the situation is w = 150 * 5 (or the other way around). Since the numbers that would be used are already stated, the equation would be as simple as that. We know that the operation would be multiplication because of the term used "150 for EACH hour" which usually indicates the operation is multiplication.

Hope I helped and good luck!
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The distance bewteen Harry and Kate is 2500 meters. Kate and Harry start walking toward one another and Kate' dog start running
Furkat [3]
Well, Kate and Harry together are walking 100 meters per minute. Which means it will take them 25 minutes to reach each other (I think). 

If the dog is running 120 meters per minute: 120 x 25 = 3,000.

The dog will run 3,000 meters (if he runs constantly to and from the spot that Kate and and Harry started).

4 0
3 years ago
Anybody solve this i made it its easy<br> 3(55x2) + 9 + 44 +88 x 9 = your number + 163593
olga55 [171]

Answer:

165*6+53+792= 990+845 = 1,835

Step-by-step explanation:

4 0
3 years ago
The class sizes of the introductory psychology courses at a college are shown below 121,134,106,93,149,130,119,128 the college a
frozen [14]
Center : Mean  Before the introduction of the new course, center = average(121,134,106,93,149,130,119,128) = 122.5  After the introduction of the new course, center =  average(121,134,106,93,149,130,119,128,45) = 113.9  The center has moved to the left (if plotted in a graph) because of the low intake for the new course.  Spread before introduction of the new course :  Arrange the numbers in ascending order:  (93, 106,119, 121), (128, 130,134, 149) Q1=median(93,106,119,121) = 112.5 Q3=median(128,130,134,149) = 132  Spread = Interquartile range = Q3-Q1 = 19.5  After addition of the new course,

 (45,93, 106,119,) 121, (128, 130,134, 149)
 Q1=median(45,93,106,119)=99.5
 Q3=median (128, 130,134, 149)= 132
 Spread = Interquartile range = 132-99.5 =32.5 
 We see that the spread has increased after the addition of the new course.
3 0
3 years ago
Read 2 more answers
Directions: FIND THE PERIMETER and SHOW YOUR WORK!
lyudmila [28]

Step-by-step explanation:

the length of unknown side =

√18²-(33-25)² =

√18²-8²= √324-64

=√260 = 16.1 ft

the perimeter= 16.1 +33+18+25

= 92.1 ft

6 0
2 years ago
Can someone help me please
Andrej [43]
It would be D because the equation just seems flipped, but the requirements of x are fulfilled.
3 0
3 years ago
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