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Butoxors [25]
4 years ago
10

What can scientists measure to provide evidence that electrons can move from one energy level to another?

Physics
2 answers:
Kitty [74]4 years ago
8 0
Light actually gets produced when electrons jump to a lower energy level so this is good evidence for this.
katen-ka-za [31]4 years ago
6 0

The energy absorbed or released by atoms.

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If a freely falling rock were equipped with a speedometer, by how much would itd speed readings increase with each second if it
Len [333]

" 20 m/s² " means that if gravity is the ONLY force on the object
(the object is in 'free fall'), then its speed increases by  20 m/s
every second.

That's the answer to your question.  Now, let me ask you
another one:

How does a speedometer tied to a falling rock work ?
How can it measure the rock's speed ?

Maybe one way would be to have a little tiny propeller on
the front of the speedometer, and it could measure how fast
the propeller is spinning as the rock falls through the air ?
Great idea.  But we already said the rock is in free-fall,
so there's no air resistance, we can't have any air, and
there's nothing to spin the propeller.

How would you do it ?  How can you measure the rock's speed ?

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4 years ago
PLEASE HELP!!!<br><br> Both Transverse and Longitudinal Waves transmit _______ and not ______.
qwelly [4]
I believe this is it

6 0
4 years ago
What is the net force on this object?​
Sergio039 [100]
200N

Explanation:
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6 0
3 years ago
I WILL MARK YOU THE BRAINLIEST NO LINKS
aliya0001 [1]

Answer:

it is 30 newtons to the left

Explanation:

6 0
3 years ago
Find an expression for the minimum frictional coefficient needed to keep a car with speed v on a banked turn of radius R designe
solniwko [45]
"v0" means that there are no friction forces at that speed
<span>mgsinΘ = (mv0²/r)cosΘ → the variable m cancels </span>
<span>sinΘ/cosΘ = tanΘ = v0² / gr 
</span><span>Θ = arctan(v0² / gr) </span>

<span>When v > v0, friction points downslope: </span>
<span>mgsinΘ + µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: </span>
<span>gsinΘ + µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ </span>
<span>µ = ((v²/r)cosΘ - gsinΘ) / (gcosΘ + (v²/r)sinΘ) </span>
<span>where Θ is defined above. </span>

<span>When v > v0, friction points upslope: </span>
<span>mgsinΘ - µ(mgcosΘ + (mv²/r)sinΘ) = (mv²/r)cosΘ → m cancels: </span>
<span>gsinΘ - µ(gcosΘ + (v²/r)sinΘ) = (v²/r)cosΘ </span>
<span>µ = (gsinΘ - (v²/r)cosΘ) / (gcosΘ + (v²/r)sinΘ) </span>
<span>where Θ is defined above. </span>
4 0
3 years ago
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