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lawyer [7]
3 years ago
6

How could you dissolve more solid solute in a saturated solution in a liquid solvent

Physics
1 answer:
tankabanditka [31]3 years ago
3 0
If you saturated the solid it will turn into liquid and soon become an air
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Suppose earth's mass increased but earth's diameter didn't change. Describe how the gravitational force between Earth and the ob
zheka24 [161]

Answer:

It increases proportionally

Explanation:

The gravitational force between the Earth and an object on its surface is given by

F=G\frac{Mm}{R^2}

where

G is the gravitational constant

M is the Earth's mass

m is the mass of the object

R is the Earth's radius

In this problem, the Earth's mass is increased, while the diameter (and therefore, the radius) doesn't change. From the equation, we see that the gravitational force is directly proportional to the Earth's mass: therefore, if the mass is increased, the force will increase as well by the same proportion (for example, if the mass is doubled, the force will double as well)

7 0
3 years ago
The melting point of potassium thiocyanate determined by a student in the laboratory turned out to be 174.5 oC. The accepted val
yaroslaw [1]

Answer:

0.75%

Explanation:

Measured value of melting point of potassium thiocyanate = 174.5 °C

Actual value of melting point of potassium thiocyanate = 173.2 °C

<em>Error in the reading = |Experimental value - Theoretical value|</em>

<em>= |174.5 - 173.2|</em>

<em>= |1.3|</em>

<em>Percentage error = (Error / Theoretical value) × 100</em>

<em>= (1.3 / 173.2)×100</em>

<em>= 0.75 %</em>

∴ Percentage error in the reading is 0.75%

4 0
3 years ago
1. Determine the magnitude of two equal but opposite charges if they attract one another with a force of 0.7N when at distance o
adell [148]

Answer:

q = 2.65 10⁻⁶ C

Explanation:

For this exercise we use Coulomb's law

        F =k \frac{q_1q_2}{r^2}

In this case they indicate that the load is of equal magnitude

       q₁ = q₂ = q

the force is attractive because the signs of the charges are opposite

       F = k \ \frac{q^2}{r^2}

       q = \sqrt{\frac{F \ r^2}{k} }

we calculate

        q = \sqrt{\frac{0.7 \ 0.3^2 }{9 \ 10^9}  }

        q = \sqrt{7 \ 10^{-12} }Ra 7 10-12

        q = 2.65 10⁻⁶ C

7 0
3 years ago
Where would you find the lowest-density seawater?
PolarNik [594]
In rivers that are close to sea
4 0
3 years ago
How do observing and inferring differ?
Illusion [34]
Observing is commenting on what you see e.g: It is raining.
Inferring is drawing conclusions from observations for example you see the road is wet so you might infer that it rained last night.
6 0
3 years ago
Read 2 more answers
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