Max: 152 million km
min 146 million km
<span>Assume: neglect of the collar dimensions.
Ď_h=(P*r)/t=(5*125)/8=78.125 MPa ,Ď_a=Ď_h/2=39 MPa
τ=(S*Q)/(I*b)=(40*〖10〗^3*π(〖0.125〗^2-〖0.117〗^2 )*121*〖10〗^(-3))/(π/2 (〖0.125〗^4-〖0.117〗^4 )*8*〖10〗^(-3) )=41.277 MPa
@ Point K:
Ď_z=(+M*c)/I=(40*0.6*121*〖10〗^(-3))/(8.914*〖10〗^(-5) )=32.6 MPa
Using Mohr Circle:
Ď_max=(Ď_h+Ď_a)/2+âš(Ď„^2+((Ď_h-Ď_a)/2)^2 )
Ď_max=104.2 MPa, Ď„_max=45.62 MPa</span>
1.Momentum is conserved
3.Kinetic energy is conserved
6.Object's bounce apart
In perfectly elastic collision, the momentum and kinetic energy of teh colliding molecule is preserved because there is no loss in energy from the collision.
Explanation:
Ideally most collisions are inelastic meaning some energy is lost in the collision mostly as heat energy. This is why in inelastic collisions, the molecules will have a reduced momentum and kinetic energy. An example of an inelastic collision is a bouncing tennis ball on the tennis court. With every bounce, it loses some energy hence its height of bounce after every bounce reduces until the ball stops bouncing.
Learn More:
For more on elastic and inelastic collisions check out;
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I believe it's B. the transmission of heat across matter
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