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Alona [7]
3 years ago
12

How to do this question plz answer me step by step plzz plz ​

Mathematics
2 answers:
Phoenix [80]3 years ago
5 0

Answer:

Step-by-step explanation:

French students=F

\frac{F}{21} =\frac{1}{3} \\F=\frac{1}{3}  \times 21 =7\\Total~ students~ of ~one~ school=21+7=28\\Total~language~students=28 \times 4=112

aliya0001 [1]3 years ago
4 0

Answer:

112

Step-by-step explanation:

Define the variables:

x = number of French students sent by the school

Write the equation:

x / 21 = 1 / 3

Solve:

x = 7

The school sent 7 French students and 21 German students, for a total of 28 students.

The other 3 schools also sent 28 students.  So the total number of students sent is:

4 × 28 = 112

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3 years ago
Write an equation of the circle with center (4,5) and radius 9.
mixer [17]

Answer:

I'm going to write both of these because maybe you have a fill in the blank question. I don't know.

(x-4)^2+(y-5)^2=9^2

Simplify:

(x-4)^2+(y-5)^2=81

Step-by-step explanation:

(x-h)^2+(y-k)^2=r^2 is the equation of a circle with center (h,k) and radius r.

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6 0
3 years ago
Read 2 more answers
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

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A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

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