Answer:
.
Step-by-step explanation:
The linear approximation is given by the equation

Linear approximation is a good way to approximate values of
as long as you stay close to the point
, but the farther you get from
, the worse your approximation.
We know that,

Next, we need to plug in the known values and calculate the value of
:

Then
.
Answer:
Third option.
Step-by-step explanation:
You need to cube both sides of the equation. Remember the Power of a power property:

![\sqrt[3]{162x^cy^5}=3x^2y(\sqrt[3]{6y^d})\\\\(\sqrt[3]{162x^cy^5})^3=(3x^2y(\sqrt[3]{6y^d}))^3\\\\162x^cy^5=27x^6y^36y^d](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%3D3x%5E2y%28%5Csqrt%5B3%5D%7B6y%5Ed%7D%29%5C%5C%5C%5C%28%5Csqrt%5B3%5D%7B162x%5Ecy%5E5%7D%29%5E3%3D%283x%5E2y%28%5Csqrt%5B3%5D%7B6y%5Ed%7D%29%29%5E3%5C%5C%5C%5C162x%5Ecy%5E5%3D27x%5E6y%5E36y%5Ed)
According to the Product of powers property:

Then. simplifying you get:

Now you need to compare the exponents. You can observe that the exponent of "x" on the right side is 6, then the exponent of "x" on the left side must be 6. Therefore:

You can notice that the exponent of "y" on the left side is 5, then the exponent of "x" on the left side must be 5 too. Therefore "d" is:

Answer:
Question 1: RS=47
Question 2: x=6
Step-by-step explanation:
Question 1:
Step 1: 3x+5=2x+15+6x-37
Step 2: 3x+5=8x-22/2
Step 3: 3x+5=4x-11
Step 4: x=16
Step 5: 2(16)+15=32+15=47
<u>RS= 47</u>
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Question 2:
Step 1: 7x+2+25x-14=180
Step 2: 32x-12=180
Step 3: 32x=192 (divide 32 from each side)
<u>x=6</u>
<u />
The answer is 300.
Explanation: 10 times 30 equals 300.
Answer:
22 Feet
Step-by-step explanation:
All the lengths of a square are the same length.
The area of a square is the length times the width. The length and the width are the same measurement. So, we are looking for the square root of 479.

21.88606863 is as far as my calculator goes. This is an irrational number. That means that it never repeats or terminates as a decimal. They tell us to answer to the nearest foot. That would be 22 feet.