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iogann1982 [59]
3 years ago
15

For this programming assignment, you have to write a Java program that tests whether a given input string represents a Valid E-m

ail address. If the input is not a valid e-mail address, it should print a message saying "Invalid Address". If the input is a valid e-mail address, it should print out the User name and the Domain name on separate lines. For purposes of this assignment and to keep the logic simple, a valid E-mail address will be of the form
Computers and Technology
1 answer:
Step2247 [10]3 years ago
8 0

Answer:

To check if the email address is correct it should have only one "@" symbol, we have to split the input string by this symbol. The code in java to achieve this is the following:

class Main {

 public static void main(String[] args) {

   String email = "[email protected]";

   String[] email_split = email.split("@");

   long count_a = email.chars().filter(ch -> ch == '@').count();

   if(count_a == 1){

     System.out.println("User name:   "+email_split[0]);

     System.out.println("Domain name: "+email_split[1]);

   }else{

     System.out.println("There is no valid email address.");

   }

 }

}

Explanation:

The explanation of the code is given below:

class Main {

 public static void main(String[] args) {

   String email = "[email protected]"; //input string to evaluate if is valid email

   long count_a = email.chars().filter(ch -> ch == '@').count(); //Count how many times the symbol @ appears

   if(count_a == 1){ //A valid email only contains one at

     String[] email_split = email.split("@"); //separate the values using the at in an array

     System.out.println("User name:   "+email_split[0]); //the first element is the username

     System.out.println("Domain name: "+email_split[1]); //the second element is the domain name

   }else{

     System.out.println("There is no valid email address."); //If there isn´t an at or are more than one then display a message saying the email is not valid

   }

 }

}

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Explanation:

//Bugs are highlighted in bold text

class Invoice

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private num balanceDue

private num tax

public void setInvoiceNUMBER(num number)

Declarations

num LOW_NUM = 1000

num HIGH_NUM = 9999

if number > HIGH_NUM then

invoiceNumber = 0

else

if number < LOW_NUM then

invoiceNumber = 0

else

invoiceNumber = num

endif

return

public void setCustomer(string cust)

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public void setBalanceDue(num balance)

//Bug balanceDue is Invoice class varible

//but it is assigned to balance .it gives error

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private void setTax()

Declarations

//Bug TAX_RATE is declared as string

//but assigned a double value

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tax = tax * TAX_RATE

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public void displayInvoice()

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//Bug

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endClass

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Invoice inv2

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//Warning

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Invoice inv4

inv1.setInvoiceNumber(1244)

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inv2.setInvoiceNumber(77777)

inv2.setCustomer("Jenkins")

inv2.setBalanceDue(2000.00)

inv2.displayInvoice()

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//Bug

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inv3.setTax(210.00)

inv3.displayInvoice()

stop

//Here is the complete program in c++

//Run the program using Microsoft visual studio 2010 vc++

#include<iostream>

#include<iomanip>

#include<string>

using namespace std;

class Invoice

{

//class varibales

private:

           int invoiceNumber;

           string customer;

           double balanceDue;

           double tax;

//class methods

public:

           void setCustomer(string cus);

           void displayInvoice();

           void setBalanceDue(double balance);

           void setInvoiceNUMBER(int number);

           void setTax();

};

void Invoice::displayInvoice()

{

cout<< setw(10)<<"Invoice #"<<setw(5)<<invoiceNumber<<endl;

cout<<setw(10)<<"Customer: "<<setw(5)<<customer<<endl;

cout<<setw(10)<<"Due: "<<setw(5)<<balanceDue<<endl;

cout<<setw(10)<<"Tax: "<<setw(5)<<tax<<endl;

//Bug

//Invoice class has no variable called balance .it should be balanceDue

cout<< "Total "<< balanceDue + tax<<endl;

}

void Invoice::setCustomer(string cust)

{

customer = cust;

}

void Invoice::setInvoiceNUMBER(int number)

{

const int LOW_NUM = 1000;

const int HIGH_NUM = 9999;

if( number > HIGH_NUM )

invoiceNumber = 0;

else

if (number < LOW_NUM )

       invoiceNumber = 0;

else

   invoiceNumber = number;

}

void Invoice::setBalanceDue(double balance)

{

balanceDue = balance;

}

void Invoice::setTax()

{

double TAX_RATE = 0.07;

tax = balanceDue * TAX_RATE;

}

int main()

{

Invoice inv1;

Invoice inv2;

Invoice inv3;

inv1.setInvoiceNUMBER(1244);

inv1.setCustomer("Brown");

inv1.setBalanceDue(1000.00);

inv1.setTax();

inv1.displayInvoice();

inv2.setInvoiceNUMBER(77777);

inv2.setCustomer("Jenkins");

inv2.setBalanceDue(2000.00);

inv2.setTax();

inv2.displayInvoice();

inv3.setInvoiceNUMBER(888);

inv3.setCustomer("Russell");

inv3.setBalanceDue(3000.00);

inv3.setTax();

inv3.displayInvoice();

system("pause");

return 0;

}

Kindly check the output image below.

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marshall27 [118]

Answer:

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Explanation:

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To determine the quantum numbers you must do the electron configuration.

Aufbau's principle is a mnemonic rule to remember the rank of the orbitals in increasing order of energy.

The rank of energy is:

1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s < 4d < 5p < 6s < 4f < 5d < 6p < 7s < 5f < 6d < 7d

You must fill the orbitals in order until you have 18 electrons:

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The last electron is in the 3p orbital.

The quantum numbers associated with the 3p orbitals are:

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Thus, the six possibilities for the last six electrons are:

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  • (3, 1, 0, +1/2)
  • (3, 1, 0, -1/2)
  • (3, 1, 1, +1/2)
  • (3, 1, 1, -1/2)

Hence, the correct choice is:

  • n = 3
  • l  = 1
  • m_l = 1
  • m_s=+1/2
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