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alina1380 [7]
3 years ago
12

Rainfall_mi is a string that contains the average number of inches of rainfall in Michigan for every month (in inches) with ever

y month separated by a comma. Write code to compute the number of months that have more than 3 inches of rainfall. Store the result in the variable num_rainy_months. In other words, count the number of items with values > 3.0.
Computers and Technology
1 answer:
const2013 [10]3 years ago
5 0

Answer:

Hi!

The answer in Javascript is:

function monthsWithMoreOfThree() {

  var Rainfall_mi = '3,4,1,5,2,6,7,9'; <em>//Defined and declared</em>

  var num_rainy_months = 0;

  var values = Rainfall_mi.split(","); <em>//use split method for Strings. Array is returned</em>

   for (var i = 0; i < values.length; i++) { <em>//for each value, compares with 3</em>

     if(values[i] > 3) { <em>//In Javascript, you can compare an String value with an int. Can use parseInt(aString) to explicit parse but is not necessary</em>

       num_rainy_months++; <em>//If value is greater than 3, adds 1 to num_rainy_months</em>

     }

   }

}

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Masja [62]

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617.5 msecs, 580.89 msecs, 582.36 msecs

Explanation:

Lets look at the following formulas:

EstimatedRTT = α * SampleRTT+(1- α) * EstimatedRTT

DevRTT = β * | SampleRTT- EstimatedRTT|+(1- β)* DevRTT

TimeoutInterval = EstimatedRTT +4* DevRTT

Given values are:

EstimatedRTT = 400 msec

DevRTT = 25 msec

α = 0.125

β = 0.25

After the first RTT estimate: (210)

EstimatedRTT = 0.125 * 210 + (1 - 0.125) * 400 = 376.25 msecs

DevRTT = 0.25 * |210 - 376.25| + (1 - 0.25) * 25 = 60.3125 msecs

TimeoutInterval = 376.25 + 4 * 60.3125 = 617.5 msecs

After the second RTT estimate: (400)

EstimatedRTT = 0.125 * 400 + (1 - 0.125) * 376.25 = 379.218 msecs

DevRTT = 0.25 * |400 - 379.218| + (1 - 0.25) * 60.3125 = 50.42 msecs

TimeoutInterval = 379.218 + 4 * 50.42 = 580.89 msecs

After the third RTT estimate: (310)

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TimeoutInterval = 370.56 + 4 * 52.95 = 582.36 msecs

5 0
3 years ago
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