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denis-greek [22]
3 years ago
11

Ella played a math game and had the five cards shown.

Mathematics
2 answers:
Gennadij [26K]3 years ago
5 0

Answer:

-5

Step-by-step explanation:

7-4+2-10= -5

GREYUIT [131]3 years ago
4 0
-5. You start with 7 then subtract 4 then add 2 then subtract 10 to get your answer.
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Me need help in math
xxMikexx [17]
The answer is d because 42/45 as a percentage is 93
7 0
3 years ago
Hello Please help me.
olga55 [171]

Answer:

Step-by-step explanation:

1) D

2) B

3) no solution

y ≤ 0.5x - 4 is area C including the red line

y ≥ 0.5x + 5 is area A including the blue line

3 0
3 years ago
Plot the point whose polar coordinates are given. Then find two other pairs of polar coordinates of this point, one with r >
Ira Lisetskai [31]

Answer:

The other pairs are:

(a)\ (2, \frac{5\pi}{6}) \to  (2, \frac{17\pi}{6}) and (-2, \frac{23\pi}{6})

(b)\ (1, -\frac{2\pi}{3}) \to (1, \frac{4\pi}{3}) and (-1, \frac{7\pi}{3})

(c)\ (-1, \frac{5\pi}{4}) \to (-1, \frac{3\pi}{4} ) and (1, \frac{7\pi}{4})

See attachment for plots

Step-by-step explanation:

Given

(a)\ (2, \frac{5\pi}{6})

(b)\ (1, -\frac{2\pi}{3})

(c)\ (-1, \frac{5\pi}{4})

Solving (a): Plot a, b and c

See attachment for plots

Solving (b): Find other pairs for r > 0 and r < 0

The general rule is that:

The other points can be derived using

(r, \theta) = (r, \theta + 2n\pi)

and

(r, \theta) = (-r, \theta + (2n + 1)\pi)

Let n =1 ---- You can assume any value of n

So, we have:

(r, \theta) = (r, \theta + 2n\pi)

(r, \theta) = (r, \theta + 2*1*\pi)

(r, \theta) = (r, \theta + 2\pi)

(r, \theta) = (-r, \theta + (2n + 1)\pi)

(r, \theta) = (-r, \theta + (2*1 + 1)\pi)

(r, \theta) = (-r, \theta + (2 + 1)\pi)

(r, \theta) = (-r, \theta + 3\pi)

(a)\ (2, \frac{5\pi}{6})

r = 2\ \ \ \ \theta = \frac{5\pi}{6}      

So, the pairs are:

(r, \theta) = (r, \theta + 2\pi)

(2, \frac{5\pi}{6}) = (2, \frac{5\pi}{6} + 2\pi)

Take LCM

(2, \frac{5\pi}{6}) = (2, \frac{5\pi+12\pi}{6})

(2, \frac{5\pi}{6}) = (2, \frac{17\pi}{6})

And

(r, \theta) = (-r, \theta + 3\pi)

(2, \frac{5\pi}{6}) = (-2, \frac{5\pi}{6} + 3\pi)

Take LCM

(2, \frac{5\pi}{6}) = (-2, \frac{5\pi+18\pi}{6})

(2, \frac{5\pi}{6}) = (-2, \frac{23\pi}{6})

The other pairs are:

(2, \frac{17\pi}{6}) and (-2, \frac{23\pi}{6})

(b)\ (1, -\frac{2\pi}{3})

r = 1\ \ \ \theta = -\frac{2\pi}{3}      

So, the pairs are:

(r, \theta) = (r, \theta + 2\pi)

(1, -\frac{2\pi}{3}) = (1, -\frac{2\pi}{3} + 2\pi)

Take LCM

(1, -\frac{2\pi}{3}) = (1, \frac{-2\pi+6\pi}{3})

(1, -\frac{2\pi}{3}) = (1, \frac{4\pi}{3})

And

(r, \theta) = (-r, \theta + 3\pi)

(1, -\frac{2\pi}{3}) = (-1, -\frac{2\pi}{3} + 3\pi)

Take LCM

(1, -\frac{2\pi}{3}) = (-1, \frac{-2\pi+9\pi}{3})

(1, -\frac{2\pi}{3}) = (-1, \frac{7\pi}{3})

The other pairs are:

(1, \frac{4\pi}{3}) and (-1, \frac{7\pi}{3})

(c)\ (-1, \frac{5\pi}{4})

r = -1 \ \ \ \ \theta = \frac{-5\pi}{4}

So, the pairs are

(r, \theta) = (r, \theta + 2\pi)

(-1, \frac{-5\pi}{4}) = (-1, \frac{-5\pi}{4} + 2\pi)

Take LCM

(-1, \frac{-5\pi}{4}) = (-1, \frac{-5\pi+8\pi}{4} )

(-1, \frac{-5\pi}{4}) = (-1, \frac{3\pi}{4} )

And

(r, \theta) = (-r, \theta + 3\pi)

(-1, \frac{-5\pi}{4}) = (-(-1), \frac{-5\pi}{4}+ 3\pi)

Take LCM

(-1, \frac{-5\pi}{4}) = (1, \frac{-5\pi+12\pi}{4})

(-1, \frac{-5\pi}{4}) = (1, \frac{7\pi}{4})

So, the other pairs are:

(-1, \frac{3\pi}{4} ) and (1, \frac{7\pi}{4})

5 0
3 years ago
The list below shows all of the possible outcomes for flipping four coins. HHHH HHHT HHTH HHTT HTHH HTHT HTTH HTTT THHH THHT THT
Anton [14]

Answer

11 over 16

Step-by-step explanation:

i have no explanation but i got it right

6 0
3 years ago
Read 2 more answers
5/8 inches minus 1/2 inches ?
Kitty [74]
5/8 - 1/2
well first you have to get the denominator the same so you multiply 1/2 by for to were it is 4/8
 so now you have 5/8 - 4/8
5/8 - 4/8 = 1/8
and you cant divide by 4 to reduce bc your already at 1 over something.
5 0
3 years ago
Read 2 more answers
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