Answer:
number one is 3 Step-by-step explanation:
number 2
the answer is 2
number 3
answer is 42
number 4 answer is 15
Part 1:
For this case we must see in the graph the axis of symmetry of the given parabola.
We have then that the axis of symmetry is the vertical line t = 2.
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, observing the graph we see that:
h (3) = 20 feet
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
Answer:
A
Step-by-step explanation:
Answer:
Step-by-step explanation:
length=1 m
base of triangle=10 m
height=5m
volume= 1/2×10×5×1=25 m cube.
slant height l=√(5²+5²)=√50=5√2
slant surface area=2[5√2×1]=10√2
area of front and back=2×1/2(10×5)=50
total surface area=50+10√2≈50+14.14≈64.14 m²
Here is how we get the answer....
First, replace f(x) with y . ...
Replace every x with a y and replace every y with an x .
Solve the equation from Step 2 for y . ...
Replace y with f−1(x) f − 1 ( x ) . ...
Verify your work by checking that (f∘f−1)(x)=x ( f ∘ f − 1 ) ( x ) = x and (f−1∘f)(x)=x ( f − 1 ∘ f ) ( x ) = x are both true.
