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3 years ago

Factor the polynomial. (Show steps please) 3x^2+5x-2

Mathematics

1 answer:

Masteriza [31]3 years ago

4 0

3x^2+5x-2=?

I think,,,,,

=>3x^2+5x-2=0

=>3x^2+3x+2x-2=0

=>3x(x+1)-2(x+1)=0

=>(3x-2)(x+1)

///////////////??///////////

=>x=2/3 & x= -1

Forgive me if wrong

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The endpoints of EF<br> are E(1,3) and F(-2,8).<br> Find EF.

Phantasy [73]

Answer:

EF = $\sqrt{34}$ ≈ 5.83

Step-by-step explanation:

Calculate EF using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = E(1, 3) and (x₂, y₂ ) = F(- 2, 8)

EF = $\sqrt{(-2-1)^2+(8-3)^2}$

= $\sqrt{(-3)^2+5^2}$

= $\sqrt{9+25}$

= $\sqrt{34}$ ≈ 5.83 ( to 2 dec. places )

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2 years ago

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3 years ago

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kaheart [24]

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2 years ago

Circles M and K are congruent, QR is congrent to LN. Find the length of QR

Novosadov [1.4K]

Given QR is congrent to LN and QR = 4x + 2 and LN = x + 7.

So, QR = LN

Hence, we can set up an equation as following:

4x + 2 = x + 7

4x + 2 - x = x + 7 - x Subtract x from each sides.

3x + 2 = 7 By simplifying.

3x + 2 - 2 = 7 - 2 Subtract 2 from each sides.

3x = 5

$\frac{3x}{3} =\frac{5}{3}$ Divide each sides by 3 to isolate x.

So, $x=\frac{5}{3}$

Next step is to plug in $x=\frac{5}{3}$ in QR = 4x+2 to get length of QR.

So, $QR = 4(\frac{5}{3})+2$

$=(\frac{20}{3})+\frac{2}{1}$ Since 2 can be written as 2/1.

By multiplying the second fraction by the common denominator 3.

$=(\frac{20}{3})+\frac{2*3}{1*3}$

$=(\frac{20}{3})+\frac{6}{3}$ By simplifying the second fraction.

$=(\frac{26}{3})$

So, $QR=\frac{26}{3}$

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3 years ago